java - EclipseLink 2.3.3 无法更新 PostgreSQL 上的版本化实体

Question

我有一个简单的实体(为简洁起见省略了一些不相关的字段):

@Entity
@Table(name = "tenant")
public class Tenant {

    @Id
    private String id;

    @Version @Column
    private long version = 0;

    @Column(name = "init_in_progress")
    private Boolean initializationInProgress;

}

我想通过使用 JPA 更新查询将 true 设置为 initializationInProgress 来对所有租户进行批量更新:

    entityManager.createQuery(
            "UPDATE Tenant t " +
            "SET t.initializationInProgress = :ip")
        .setParameter("ip", initializationInProgress)
        .executeUpdate();

这适用于 EclipseLink 2.2.1。但是，当我对 2.3.3 版本尝试相同操作时，出现错误:

Caused by: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.3.3.v20120629-r11760): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERROR: more than one row returned by a subquery used as an expression
Error Code: 0
Call: UPDATE tenant SET version = (SELECT (version + ?) FROM tenant WHERE ID = tenant.ID), init_in_progress = ?
    bind => [1, true]
Query: UpdateAllQuery(referenceClass=Tenant sql="UPDATE tenant SET version = (SELECT (version + ?) FROM tenant WHERE ID = tenant.ID), init_in_progress = ?")
    at org.eclipse.persistence.exceptions.DatabaseException.sqlException(DatabaseException.java:333)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.processExceptionForCommError(DatabaseAccessor.java:1494)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:838)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeNoSelect(DatabaseAccessor.java:906)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.basicExecuteCall(DatabaseAccessor.java:592)
    at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeCall(DatabaseAccessor.java:535)
    at org.eclipse.persistence.internal.sessions.AbstractSession.basicExecuteCall(AbstractSession.java:1717)
    at org.eclipse.persistence.sessions.server.ClientSession.executeCall(ClientSession.java:253)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:207)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeCall(DatasourceCallQueryMechanism.java:193)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.executeNoSelectCall(DatasourceCallQueryMechanism.java:236)
    at org.eclipse.persistence.internal.queries.DatasourceCallQueryMechanism.updateAll(DatasourceCallQueryMechanism.java:789)
    at org.eclipse.persistence.queries.UpdateAllQuery.executeDatabaseQuery(UpdateAllQuery.java:153)
    at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:844)
    at org.eclipse.persistence.queries.DatabaseQuery.executeInUnitOfWork(DatabaseQuery.java:743)
    at org.eclipse.persistence.queries.ModifyAllQuery.executeInUnitOfWork(ModifyAllQuery.java:145)
    at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2871)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1516)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1498)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1463)
    at org.eclipse.persistence.internal.jpa.EJBQueryImpl.executeUpdate(EJBQueryImpl.java:540)
    at com.example.dao.impl.tenant.TenantRepositoryImpl.updateAllTenantsInitializationStatus(TenantRepositoryImpl.java:100)

有人熟悉这个错误吗？任何已知的解决方法/修复(除了不更改 EclipseLink 版本)？感谢您的帮助。

顺便说一句，我正在使用 PostgreSQL 9.1。

Answer 1

这最初看起来像是一个数据问题，您在 tenant 中有多个具有相同 ID 的行……但这实际上是 EclipseLink 查询的问题。由于这是一个生成的查询，您手上似乎有一个(严重的)EclipseLink 错误。

更新:参见 this EclipseLink bugzilla entry for bug 393223 .

查询应该真正为 tenant 的内部引用起别名，例如:

UPDATE tenant SET version = (SELECT (t2.version + ?) FROM tenant t2 WHERE t2.ID = tenant.ID), init_in_progress = ?

添加此别名失败意味着 ID = tenant.ID 意味着 tenant.ID = tenant.ID ...始终为真，因此子查询匹配每个租户行。

观察这个演示:

CREATE TABLE tenant ( ID integer primary key, version integer );
INSERT INTO tenant ( id, version ) values (1,0), (2,0), (3,0);

BEGIN;

PREPARE testq(integer) AS 
UPDATE tenant SET version = (SELECT (version + $1) FROM tenant WHERE ID = tenant.ID);

regress=> EXECUTE testq(1);
ERROR:  more than one row returned by a subquery used as an expression

ROLLBACK;

更正查询:

BEGIN;

PREPARE testq2(integer) AS 
UPDATE tenant SET version = (SELECT (version + $1) FROM tenant t2 WHERE t2.ID = tenant.ID);

regress=> EXECUTE testq2(1);
UPDATE 3

ROLLBACK;

这似乎是 EclipseLink 错误。除了作为 native SQL 进行批量更新之外，我看不到您可以在代码中做很多事情。