postgresql - postgresql 中的滞后计算

Question

我有一个包含以下数据的表:计算列:当前

| id | Date (dd/mm/yyyy) | Factor | Actual | Current  |
|----|-------------------|--------|--------|----------|
| 1  |     04/01/2017    | 0.5    | 100    | 100      |
| 2  |     04/02/2017    | 0.5    | 120    | 100      |
| 3  |     04/03/2017    | 0.5    | 120    | 110      |
| 4  |     04/04/2017    | 0.5    | 115    | 115      |
| 5  |     04/05/2017    | 0.5    | 125    | 115      |
| 6  |     04/06/2017    | 0.5    | 100    | 120      |
| 7  |     04/07/2017    | 0.5    | 100    | 110      |

当前行 = 上一行当前值 + 因子 *(上一行实际值 - 上一行当前值)

    For id = 1, current = same as actual = 100
    For id = 2, current = 100 + 0.5 * (100 - 100) = 100
    For id = 3, current = 100 + 0.5 * (120 - 100) = 110
    For id = 4, current = 110 + 0.5 * (120 - 110) = 115 
and so on...

如何在postgresql中实现使用查询？

Answer 1

你需要一个递归查询。

with recursive my_table_with_rn as 
(
    select *, row_number() over (order by id) as rn
    from my_table
),

rec_query(rn, id, date, factor, actual, current) as 
(
    select rn, id, date, factor, actual, actual
    from my_table_with_rn
    where rn = 1

union all

    select 
        t.rn, t.id, t.date, t.factor, t.actual, 
        p.current + t.factor * (p.actual - p.current)
    from rec_query p
    join my_table_with_rn t on t.rn = p.rn + 1
)

select id, date, factor, actual, current
from rec_query
order by id;

请注意，添加了 row_number() 以在 ids 不连续的情况下工作(实际数据不需要，您可以使用 id 而不是 rn)。

Test it here.