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我尝试从多个表中提取数据集,然后在提取数据时计算年龄,但无法使用 round 来计算年龄。
建议会很棒!
SELECT client.ClientNumber
, client.ClientActive AS Active
, invoice.ClientNumber
, invoice.InvoiceDate AS InvoiceDate
, invoicedetail.InvoiceNumber AS Invoice
, invoicedetail.ClientNumber
, invoicedetail.Extended AS Cost
, invoicedetail.ServiceDate AS Serviced
FROM
dbo.client
INNER JOIN dbo.invoice
ON client.ClientNumber = invoice.ClientNumber
INNER JOIN dbo.invoicedetail
ON invoice.ClientNumber = invoicedetail.ClientNumber
WHERE
client.ClientActive = 'Y'
GROUP BY
client.ClientNumber
, client.ClientActive
, invoice.ClientNumber
, invoice.InvoiceDate
, invoicedetail.InvoiceNumber
, invoicedetail.ServiceDate
, invoicedetail.Extended
, invoicedetail.ClientNumber
, invoicedetail.ClientNumber
ORDER BY
InvoiceDate
ROUND(DATEDIFF(hour,CASE WHEN [InvoiceDate]>= GETDATE() THEN NULL ELSE [InvoiceDate] END, getdate())/8766.0,2) AS [ClientAge],
(CASE WHEN ROUND(DATEDIFF(hour,CASE WHEN [InvoiceDate]>= GETDATE() THEN NULL ELSE [InvoiceDate] END, getdate())/8766.0,2)< 0.5 THEN '0-5 months'
WHEN ROUND(DATEDIFF(hour,CASE WHEN [InvoiceDate]>= GETDATE() THEN NULL ELSE [InvoiceDate] END, getdate())/8766.0,2) BETWEEN 0.5 AND 0.99 THEN '6-11 months'
WHEN ROUND(DATEDIFF(hour,CASE WHEN [InvoiceDate]>= GETDATE() THEN NULL ELSE [InvoiceDate] END, getdate())/8766.0,2) BETWEEN 1 AND 5.99 THEN '1-5 years'
WHEN ROUND(DATEDIFF(hour,CASE WHEN [InvoiceDate]>= GETDATE() THEN NULL ELSE [InvoiceDate] END, getdate())/8766.0,2) BETWEEN 6 AND 10.99 THEN '6-10 years'
WHEN ROUND(DATEDIFF(hour,CASE WHEN [InvoiceDate]>= GETDATE() THEN NULL ELSE [InvoiceDate] END, getdate())/8766.0,2) BETWEEN 11 AND 15.99 THEN '11-15 years'
WHEN ROUND(DATEDIFF(hour,CASE WHEN [InvoiceDate]>= GETDATE() THEN NULL ELSE [InvoiceDate] END, getdate())/8766.0,2)>=16 THEN '16+ years'
END) as [ClientAgeGroup]
最佳答案
如果您希望将 ROUND
的结果包含在结果集中,则需要将其移至 SELECT
之后的字段列表中:
SELECT client.ClientNumber
, client.ClientActive AS Active
, invoice.ClientNumber
, invoice.InvoiceDate AS InvoiceDate
, invoicedetail.InvoiceNumber AS Invoice
, invoicedetail.ClientNumber
, invoicedetail.Extended AS Cost
, invoicedetail.ServiceDate AS Serviced
, ROUND(DATEDIFF(hour,CASE WHEN InvoiceDate>= GETDATE() THEN NULL ELSE InvoiceDate END, getdate())/8766.0,2) AS [ClientAge],
(CASE WHEN ROUND(DATEDIFF(hour,CASE WHEN InvoiceDate>= GETDATE() THEN NULL ELSE InvoiceDate END, getdate())/8766.0,2)< 0.5 THEN '0-5 months'
WHEN ROUND(DATEDIFF(hour,CASE WHEN InvoiceDate>= GETDATE() THEN NULL ELSE InvoiceDate END, getdate())/8766.0,2) BETWEEN 0.5 AND 0.99 THEN '6-11 months'
WHEN ROUND(DATEDIFF(hour,CASE WHEN InvoiceDate>= GETDATE() THEN NULL ELSE InvoiceDate END, getdate())/8766.0,2) BETWEEN 1 AND 5.99 THEN '1-5 years'
WHEN ROUND(DATEDIFF(hour,CASE WHEN InvoiceDate>= GETDATE() THEN NULL ELSE InvoiceDate END, getdate())/8766.0,2) BETWEEN 6 AND 10.99 THEN '6-10 years'
WHEN ROUND(DATEDIFF(hour,CASE WHEN InvoiceDate>= GETDATE() THEN NULL ELSE InvoiceDate END, getdate())/8766.0,2) BETWEEN 11 AND 15.99 THEN '11-15 years'
WHEN ROUND(DATEDIFF(hour,CASE WHEN InvoiceDate>= GETDATE() THEN NULL ELSE InvoiceDate END, getdate())/8766.0,2)>=16 THEN '16+ years'
END) as [ClientAgeGroup]
FROM
dbo.client
INNER JOIN dbo.invoice
ON client.ClientNumber = invoice.ClientNumber
INNER JOIN dbo.invoicedetail
ON invoice.ClientNumber = invoicedetail.ClientNumber
WHERE
client.ClientActive = 'Y'
GROUP BY
client.ClientNumber
, client.ClientActive
, invoice.ClientNumber
, invoice.InvoiceDate
, invoicedetail.InvoiceNumber
, invoicedetail.ServiceDate
, invoicedetail.Extended
, invoicedetail.ClientNumber
, invoicedetail.ClientNumber
ORDER BY
InvoiceDate
关于MySQL: 'ROUND' 附近的语法不正确,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23375249/
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