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php - 插入 PDO 不起作用

转载 作者:行者123 更新时间:2023-11-29 12:42:06 24 4
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过去一小时我一直在努力让它发挥作用。我已经检查了所有链接,并且引用了正确的表格。我从 Documents.php 中删除了 if 语句并进行了检查,但没有任何内容将数据插入到表中。我还检查了错误日志,没有收到任何错误。

index.php

<div class="content">
<?php if (Session::get('user_logged_in') == true AND $admin == 1):?>
<form action="../processes/documents.php" method="post" class="pure-form pure-form-aligned">
<legend>Add Document</legend>
<fieldset>
<div class="pure-control-group">
<input type="text" name="documentnumber" placeholder="Document Number">
</div>
<div class="pure-control-group">
<input type="text" name="documentdate" placeholder="Document Date">
</div>
<div class="pure-control-group">
<input type="text" name="expirationdate" placeholder="Document Expiration Date">
</div>
<div class="pure-control-group">
<input type="text" name="description" placeholder="Description">
</div>
<div class="pure-control-group">
<select name="artistname">
<?php
$con=mysqli_connect("$hostname","$username","$password","saintfiv_artists");
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result2 = mysqli_query($con,"SELECT * FROM artists ORDER BY `artistname`");

while($row2 = mysqli_fetch_array($result2))
{
echo '<option value="' . $row2['artistname'] . '">' . $row2['artistname'] . '</option>';
}
?>
</select>
</div>
<div class="pure-control-group">
<select name="artwork">';
<?php
$dir = '../documents/';
$files = scandir($dir);
foreach ($files as $filename) {
if ($filename != '.' AND $filename != ".."){
echo "<option value='" . $filename . "'>".$filename."</option>";
}
}
?>
</select>
</div>
<div class="pure-control-group">
<button type="submit" name="adddocument" class="pure-button pure-button-primary">Add</button>
</div>
</fieldset>
</form>
<?php endif; ?>
</div>

文档.php

<?php
if (isset($_POST['adddocument'])) {
include_once('../config/mysql.php');

$document_number = $_POST['documentnumber'];
$document_date = $_POST['documentdate'];
$document_expiration_date = $_POST['expirationdate'];
$description = $_POST['description'];
$artist_name = $_POST['artistname'];
$document_name = $_POST['documentname'];

try {
$dbh = new PDO("mysql:host=$hostname;dbname=saintfiv_artists", $username, $password);
$stmt = $dbh->prepare("INSERT INTO documents(`document_number`, `document_date`, `document_expiration_date`, `description`, `artist_name`, `document_name`) VALUES (:document_number, :document_date, :document_expiration_date, :description, :artist_name, :document_name)");
$stmt->bindParam(':document_number', $document_number, PDO::PARAM_STR);
$stmt->bindParam(':document_date', $document_date, PDO::PARAM_STR);
$stmt->bindParam(':document_expiration_date', $document_expiration_date, PDO::PARAM_STR);
$stmt->bindParam(':description', $description, PDO::PARAM_STR);
$stmt->bindParam(':artist_name', $artist_name, PDO::PARAM_STR);
$stmt->bindParam(':document_name', $document_name, PDO::PARAM_STR);
$stmt->execute();
}
catch(PDOException $e)
{
echo $e->getMessage();
}
}

header("Location: http://www.saint57records.com/artistreports/documents/index");
?>

最佳答案

"Fred, your error reporting suggestion helped me find my problem. Please add your comment as the answer. "

根据OP的要求,评论回答以结束问题。

添加:

$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

连接打开后。

另外,添加error reporting打开后立即到文件顶部 <?php标签

error_reporting(E_ALL); 
ini_set('display_errors', 1);

看看它是否产生任何结果,因为您没有检查潜在的错误。

关于php - 插入 PDO 不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25965084/

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