mysql - 不喜欢来自两个表

Question

我正在尝试从表 A 中获取具有特定 MeetingID 的表 B 中不存在的所有用户名就像 iam 尝试获取 Meetingid: 2 一样，表 A 应该返回“Tested”用户，并将其余内容排除在外。 MeetingID 6 返回测试。这可以通过一个查询实现吗？

Table A: ID, Username 1 Test 2 Tested 3 Testood

Table B: Meetingid, Username 2 Test 2 Testood 6 Tested 6 Testood

这是我一直在尝试工作的代码:

SELECT members.username FROM members RIGHT JOIN attendmeeting ON
attendmeeting.username=members.username WHERE attendmeeting.username
NOT LIKE members.username ORDER BY username DESC

表 A 是成员，表 B 是出席 session 。我不知道如何根据 session ID 过滤掉它。

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编辑:感谢 Harsh Gupta，第一部分现在正在工作。最后一件事是过滤掉“不喜欢”仅对这些成员使用特定的 session ID。

当前代码:

SELECT members.username 
FROM members 
LEFT JOIN attendmeeting 
ON attendmeeting.username = members.username 
WHERE attendmeeting.username IS NULL 
ORDER BY members.username DESC

Answer 1

我不确定您的 tableA 和 tableB 是哪一个:

SELECT members.username 
FROM members 
LEFT JOIN attendmeeting 
ON attendmeeting.username = members.username 
WHERE attendmeeting.username IS NULL 
ORDER BY members.username DESC

编辑:

SELECT members.username 
FROM members 
LEFT JOIN attendmeeting 
ON attendmeeting.username = members.username 
WHERE attendmeeting.username IS NULL
    AND attendmeeting.username = 2
ORDER BY members.username DESC

HTH