php - 检查两个日期不在两个另一个日期之间 + MYSQl

Question

我正在查询酒店预订和预订系统，但遇到选择两个日期之间未预订的房间的问题。我的查询与此类似，但它不起作用，并且查询返回注意到，但实际上我有 3 个房间，房间类型为 1 。SQL fiddle :http://sqlfiddle.com/#!2/b97419

SELECT tbl_room.room_no, tbl_room.type_id, tbl_Reservation.room_id
FROM tbl_room
LEFT JOIN tbl_Reservation ON tbl_room.id = tbl_Reservation.room_id
WHERE (
(
tbl_Reservation.checkin_data < '" . $checkin . "'
AND tbl_Reservation.checkout_data < '" . $checkin . "'
)
OR (
tbl_Reservation.checkin_data > '" . $checkout . "'
AND tbl_Reservation.checkout_data > '" . $checkout . "'
)
)
AND tbl_room.type_id =1

感谢您的帮助，并对我的英语不好表示歉意。

Answer 1

尝试这样的事情

SELECT 
    tbl_room.room_no, 
    tbl_room.type_id, 
    tbl_room.id,

    tr.id as reserv_status

FROM tbl_room

 LEFT JOIN tbl_Reservation tr ON tbl_room.id = tr.room_id AND 
           (
             (tr.checkin_data <= "'$checkin'" AND tr.checkout_data >= "'$checkin'")
             OR
             (tr.checkin_data <= "'$checkout'" AND tr.checkout_data >= "'$checkout'")
           )

 WHERE 

 tbl_room.type_id =1  AND tr.id IS NULL