mysql - Sql 选择顶部查询

Question

大家好，我有以下问题:

   SELECT TOP(1) CommitmentLog.CommitAmt
FROM   leveldetails
       INNER JOIN CommitmentLog
               ON leveldetails.App_ID = CommitmentLog.app_id
                  AND leveldetails.Intro_ID = '999'
                  AND leveldetails.Side = 'right'
                  AND CommitmentLog.flag != '1'
                  AND CommitmentLog.CommitNo NOT IN (SELECT commit_no
                                                     FROM   binary_bal
                                                     WHERE  Intro_ID = '999'
                                                            AND Side = 'right'
                                                            AND llevel BETWEEN 1 AND 100000) 

第一行 CommitAmt 值:1500
第二行 CommitAmt 值:500
如果我选择 CommitmentLog.CommitAmt 的前 1 个总和，则返回值为 2000 而不是 1500
如果我选择 CommitmentLog.CommitAmt 的前 2 个总和，则返回值 2000 是正确的

if i select top 1 then sum(CommitmentLog.CommitAmt) it should return 1500 and
if i select top 2 then sum(CommitmentLog.CommitAmt) it should return 1500 + 500 = 2000

Answer 1

您想对结果集中的前 N ​​个求和吗？试试这个

SELECT SUM(t1.CommitAmt) from (SELECT TOP(1) CommitmentLog.CommitAmt
                                  FROM   leveldetails
                                    INNER JOIN CommitmentLog
                                      ON leveldetails.App_ID = CommitmentLog.app_id
                                      AND leveldetails.Intro_ID = '999'
                                      AND leveldetails.Side = 'right'
                                      AND CommitmentLog.flag != '1'
                                      AND CommitmentLog.CommitNo NOT IN (SELECT commit_no
                                                     FROM   binary_bal
                                                     WHERE  Intro_ID = '999'
                                                            AND Side = 'right'
                                                            AND llevel BETWEEN 1 AND 100000)
                              ) AS t1