php - 如何从 mysql 获取行到表头以及与获取的表头相关的特定数据

Question

我有 2 个表 question_details 和 paid_response

question_details 包含

 qno  qshortcode
 504   what do you want
 515   what is your name
 541   what is your address
  .
  .
 other..  others question

paid_response 包含

 qno   paid_respo   paid_rev    sys_date
 504    yes         0.60       2014-12-16 04:14:40
 515    no          0.42       2014-12-17 04:14:40 

现在我想要来自 question_details 的 qshortcode 以及给定的 qno(504 和 515) 以及来自 paid_response 表的paid_respo其中 pay_rev not=0.00 并且在两个日期之间

what do you want    what is your name   //fetching from `question_details` table
yes                  no                 //fetching from `paid_response` table with respect to `qno` where paid_rev not 0.00

我的代码用于从question_details`表中获取qshortcode

<?php
//DB connection goes here

$query=mysql_query("select qshortcode from question_details where qno=504 or qno='515'");   
echo '<tr>';
for($i = 0; $row = mysql_fetch_array($query);$i++) {
echo '<td>'.$row['qshortcode'].'</td>';           
echo '</tr>';                        
} ?>     

它的抓取就像

what do you want what is your name

 //cant fetch paid_respo of specific qshortcode below this where paid_rev not euqals to 0.00 or blank

Answer 1

尝试使用这个:使用联接来合并两个表

<?php
//DB connection goes here

$query=mysql_query("select qshortcode,paid_respo from question_details left join paid_response on paid_response.qno=question_details.qno  where question_details.qno in (504,515)");   


     echo '<table>';
        while ($row = mysql_fetch_array($query)) {
        echo '<tr>';//to show each response as one row.
        echo '<td>'.$row['qshortcode'].'</td>';//what do you want
        echo '<td>'.$row['paid_respo'].'</td>';//yes            
        echo '</tr>';                        
        } 
    echo '</table>'

?>