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MySQL 简单 COUNT 花费很长时间

转载 作者:行者123 更新时间:2023-11-29 12:29:26 26 4
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我有一个包含超过 870.000 行的数据库。每次收到请求时,我都必须执行 COUNT 来检查行是否存在。这些 COUNT 请求最多需要 180 秒才能执行。这是相当长的。

这是我的查询:

SELECT COUNT(0) AS aantal FROM milk_quotes WHERE shopId = '438' AND quoteId = '17424765'

解释扩展显示:

id  select_type table   type    possible_keys   key key_len ref rows    filtered    Extra
1 SIMPLE milk_quotes ref shopId shopId 4 const 87648 100.00 Using where

表结构为:

CREATE TABLE `milk_quotes ` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`shopId` mediumint(11) DEFAULT NULL,
`quoteId` bigint(11) DEFAULT NULL,
`customerId` bigint(11) DEFAULT NULL,
`customerIP` int(11) unsigned DEFAULT NULL,
`recoveryHash` char(32) CHARACTER SET latin1 DEFAULT NULL,
`language` varchar(2) CHARACTER SET latin1 DEFAULT 'nl',
`channel` varchar(11) CHARACTER SET latin1 DEFAULT NULL,
`productsCount` int(11) DEFAULT NULL,
`isPaid` tinyint(1) DEFAULT '0',
`isNotified` enum('0','1') CHARACTER SET latin1 DEFAULT '0',
`paymentId` varchar(50) CHARACTER SET latin1 DEFAULT NULL,
`paymentCountry` varchar(2) CHARACTER SET latin1 DEFAULT NULL,
`priceIncl` decimal(10,2) DEFAULT NULL,
`createdAt` timestamp NULL DEFAULT CURRENT_TIMESTAMP,
`updatedAt` timestamp NULL DEFAULT NULL,
`shopUpdatedAt` timestamp NULL DEFAULT NULL,
`recalculatedAt` timestamp NULL DEFAULT NULL,
`shopCreatedAt` timestamp NULL DEFAULT NULL,
`firstReminder` mediumint(9) DEFAULT NULL,
`secondReminder` mediumint(9) DEFAULT NULL,
`thirdReminder` mediumint(9) DEFAULT NULL,
`skipQuote` enum('1','0') DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `isPaid` (`isPaid`),
KEY `shopId` (`shopId`),
KEY `firstReminder` (`firstReminder`)
) ENGINE=InnoDB AUTO_INCREMENT=930952 DEFAULT CHARSET=utf8;

Inno DB 变量:

have_innodb YES
ignore_builtin_innodb OFF
innodb_adaptive_hash_index ON
innodb_additional_mem_pool_size 1048576
innodb_autoextend_increment 8
innodb_autoinc_lock_mode 1
innodb_buffer_pool_size 8388608
innodb_checksums ON
innodb_commit_concurrency 0
innodb_concurrency_tickets 500
innodb_data_file_path ibdata1:10M:autoextend
innodb_data_home_dir
innodb_doublewrite ON
innodb_fast_shutdown 1
innodb_file_io_threads 4
innodb_file_per_table OFF
innodb_flush_log_at_trx_commit 1
innodb_flush_method
innodb_force_recovery 0
innodb_lock_wait_timeout 50
innodb_locks_unsafe_for_binlog OFF
innodb_log_buffer_size 1048576
innodb_log_file_size 5242880
innodb_log_files_in_group 2
innodb_log_group_home_dir ./
innodb_max_dirty_pages_pct 90
innodb_max_purge_lag 0
innodb_mirrored_log_groups 1
innodb_open_files 300
innodb_rollback_on_timeout OFF
innodb_stats_on_metadata ON
innodb_support_xa ON
innodb_sync_spin_loops 20
innodb_table_locks ON
innodb_thread_concurrency 8
innodb_thread_sleep_delay 10000
innodb_use_legacy_cardinality_algorithm ON

最佳答案

一个查询在每个查询中每个表只能使用一个索引;因此,如果您在单个查询中查找多个字段,则需要有一个涵盖所有字段的索引。在您的查询中,使用了 shopId 索引,但在该 quoteId 中按顺序扫描,这不太好(我假设有一堆 quoteId每个商店都有几行,是吗?)。尝试将架构中的 shopId 索引更改为

KEY `shopAndQuoteIds` (`shopId`, `quoteId`),

(如果您想在现有表上执行此操作,我相信 ALTER TABLE aantal DROP INDEX shopId 后跟 ALTER TABLE aantal ADD KEY shopAndQuoteIds (shopId, quoteId)应该这样做。在执行此操作之前,请备份您的数据库!或者,您可以转储表,将架构更改为上述内容,然后将其重新导入回来。)

请注意,可以使用键的任何前缀;因此 (shopId, quoteId) 索引可用于 shopId 查询和 shopId + quoteId 查询,但是不适用于 quoteId 查询。事实上,它仍然可以用于普通的 shopId 查询,这意味着通过创建这个新索引并删除旧的 shopId 索引,您不会有任何损失。

关于MySQL 简单 COUNT 花费很长时间,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27794269/

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