mysql - 通过基于最大值的连接获取完整行

Question

在 mysql 中我有这两个表:

**Seasons**
id
number
current

**Episodes**
id
number
season_id
other_info

我想从 Episodes 获取完整行，从 Seasons 获取连接行，所有这些都基于两个表的最大 number 值。

例如，如果我有第 1、2、3 季，我想获取最近一季的最新剧集。

我从这个查询开始:

SELECT e.id as episode_id, s.id as season_id, MAX(s.number) AS season_number, MAX(e.number) AS episode_number, e.other_info
FROM (episodes AS e)
JOIN seasons AS s ON e.season_id=s.id
WHERE s.current =  1

它确实有效，但随后它显示了错误的 other_info 值。我知道这是因为 MAX() 对行进行分组，但其他值是随机的，所以我认为它只是显示第一行可用的 other_info 。

环顾四周，我发现了这个，我认为它会起作用，但它没有:

SELECT e.id as episode_id, s.id as season_id, MAX(s.number) AS season_number, MAX(e.number) AS episode_number, e.other_info
FROM (episodes AS e)
JOIN seasons AS s ON e.season_id=s.id
WHERE s.current =  1 AND
e.number = (select max(sube.number) from episodes sube);

在这种情况下，我只得到所有 NULL 值。

Answer 1

我认为这会对您有所帮助:

SELECT seasons.*, episodes.* 
FROM episodes
INNER JOIN seasons ON episodes.season_id = seasons.id
ORDER BY seasons.number DESC ,episodes.number DESC 
limit 0,1