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php - SQL 语法错误 select * from

转载 作者:行者123 更新时间:2023-11-29 12:24:20 25 4
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我的代码抛出此错误:

Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-contact-info' at line 1

我的代码:

<?php

//connect
$connection = mysqli_connect("myh","myu","myp","mydb") or die("Error " . mysqli_error($connection));

//consultation:
$query = "SELECT * FROM web-contact-info";

//execute the query.
$result = mysqli_query($connection, $query);
if (!$result) {
printf("Error: %s\n", mysqli_error($connection));
exit();
}

//display information:
while($row = mysqli_fetch_array($result)) {
echo $row["live_name"] . "<br>";
}

?>

我尝试在 web-contact-info 周围加上引号,但得到了略有不同的错误:

Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''web-contact-info'' at line 1

我写错了什么?

最佳答案

你可以试试这个:

SELECT * FROM `web-contact-info`

由于 mysql_* 已弃用,请考虑切换到 mysqliPDO .

关于php - SQL 语法错误 select * from,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28568657/

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