ios - 使用 AssetPath 创建 NSURL

Question

使用 UIImagePickerController，我能够获取媒体的 Assets 路径，例如 assets-library://asset/asset.MOV?id=2A2CE6C9-C178-4395-977B-E6F159BF6D5E&ext=MOV.

NSURL *instagramURL = [NSURL URLWithString:[NSString stringWithFormat:@"instagram://library?AssetPath=%@&InstagramCaption=%@",[referenceURL absoluteString], strInstagramCaption]];

现在，我想将此 Assets 路径转换为 ​​NSURL 以将其传递到以下代码块中:

if ([[UIApplication sharedApplication] canOpenURL:instagramURL])
{
    [[UIApplication sharedApplication] openURL:instagramURL];
}

Answer 1

这是将 Assets 路径转换为有效 NSUrl 的方式:-

NSURL *instagramURL = [NSURL URLWithString:[[NSString stringWithFormat:@"instagram://library?AssetPath=%@&InstagramCaption=%@",[assetURL absoluteString],caption]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
    if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) {
        [[UIApplication sharedApplication] openURL:instagramURL];
    }

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