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mysql - 包含表时 Sequelize 返回 "Unknown column"

转载 作者:行者123 更新时间:2023-11-29 12:19:24 24 4
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这个想法是获取与调用服务器上的作业关联的号码。每项工作都有一堆与之相关的数字。当有人回电时,我需要获取与来电显示关联的作业。

导致问题的查询:

    // Look for messages to play
db.job.find( {
'where': { 'status' : [ 'new', 'inprogress', 'done' ] },
// 'limit' : 1, // Obviously
'order' : [[ 'jobID' , 'DESC' ]], // Latest
'include' : [
{
'model' : db.number,
'where' : { 'number' : this.number }
}
]
} ).complete( ... );

数据库片段:

var job = sequelize.define( 'job', {
'id': {
type: Sequelize.INTEGER( 10 ),
field: 'job_id',
allowNull: false,
primaryKey: true,
autoIncrement: true
},
'externalID' : {
type: Sequelize.STRING( 45 ),
field: 'external_id',
allowNull: false,
unique: true,
validate: {
notEmpty: true
}
},
'status' : {
type: Sequelize.STRING( 16 ),
field: 'status',
allowNull: false,
defaultValue: 'processing'
},
'filename' : {
type: Sequelize.STRING( 64 ),
field: 'filename',
allowNull: true
}
}, {
'createdAt' : 'created',
'updatedAt' : 'modified',
'tableName' : 'jobs'
} );

var number = sequelize.define( 'number', {
'id': {
type: Sequelize.BIGINT( 20 ),
field: 'number_id',
allowNull: false,
primaryKey: true,
autoIncrement: true
},
'jobID': {
type: Sequelize.INTEGER( 10 ),
field: 'job_id',
allowNull: false
},
'externalID' : {
type: Sequelize.STRING( 45 ),
field: 'external_id',
allowNull: false,
unique: true,
validate: {
notEmpty: true
}
},
'number' : {
type: Sequelize.STRING( 16 ),
field: 'number',
allowNull: false,
validate: {
notEmpty: true
}
},
'extension' : {
type: Sequelize.STRING( 16 ),
field: 'extension',
allowNull: true
},
'status' : {
type: Sequelize.STRING( 16 ),
field: 'status',
allowNull: false,
defaultValue: 'new'
},
'lastCall' : {
type: Sequelize.DATE,
field: 'last_call',
allowNull: true
},
'tries' : {
type: Sequelize.INTEGER,
field: 'tries',
allowNull: false,
defaultValue: 0
},
}, {
'createdAt' : 'created',
'updatedAt' : 'modified',
'tableName' : 'numbers'
} );

job.hasMany( number, { 'foreignKey' : 'job_id' } );
number.belongsTo( job, { 'foreignKey' : 'job_id' } );

它生成的查询是这样的:

SELECT `job`.*,
`numbers`.`number_id` AS `numbers.id`,
`numbers`.`job_id` AS `numbers.jobID`,
`numbers`.`external_id` AS `numbers.externalID`,
`numbers`.`number` AS `numbers.number`,
`numbers`.`extension` AS `numbers.extension`,
`numbers`.`status` AS `numbers.status`,
`numbers`.`last_call` AS `numbers.lastCall`,
`numbers`.`tries` AS `numbers.tries`,
`numbers`.`created` AS `numbers.created`,
`numbers`.`modified` AS `numbers.modified`,
`numbers`.`job_id` AS `numbers.job_id`
FROM
(SELECT `job`.`job_id` AS `id`,
`job`.`external_id` AS `externalID`,
`job`.`status`,
`job`.`filename`,
`job`.`created`,
`job`.`modified`
FROM `jobs` AS `job`
WHERE `job`.`status` IN ('new',
'inprogress',
'done')
AND
(SELECT `job_id`
FROM `numbers` AS `numbers`
WHERE `job`.`id` = `numbers`.`job_id`
AND `numbers`.`number` IN ('5556656565') LIMIT 1) IS NOT NULL
ORDER BY `job`.`jobID` DESC LIMIT 1) AS `job`
INNER JOIN `numbers` AS `numbers` ON `job`.`id` = `numbers`.`job_id`
AND `numbers`.`number` IN ('5556656565')
ORDER BY `job`.`jobID` DESC;

正如您从表结构中看到的那样,出现了此错误:

error: Callback: Error fetching job via number. SequelizeDatabaseError: ER_BAD_FIELD_ERROR: Unknown column 'job.id' in 'where clause'

我哪里出错了?

最佳答案

实际上,这似乎是一个悬而未决的问题。

https://github.com/sequelize/sequelize/issues/3403

关于mysql - 包含表时 Sequelize 返回 "Unknown column",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29266422/

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