ios - 应用程序在搜索(过滤)NSDictionary 时崩溃

Question

所以我有以下代码:

我的 .h 文件

    @interface TableViewController : UITableViewController <UISearchBarDelegate,UITableViewDataSource,UITableViewDelegate>
{
    IBOutlet UITableView *myTableView;
    IBOutlet UISearchBar *mysearchBar;
        NSMutableArray *filteredList;
     BOOL isFiltered;
}
@property NSDictionary *iconSet;

@end

以及 .m 文件中出错的部分。

-(void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText{

if(searchText.length == 0)
{
    //bool in .h file
    isFiltered = NO;
}else
{
    isFiltered = YES;
    filteredList = [[NSMutableArray alloc] init];

    //self.iconSet is an NSDictionary (coming from a segue) formed like -(NSDictionary *) symbols { return self.symbols = @{@"💘":@"Heart With Arrow",@"❤️":@"Heavy Black Heart"}
    for (NSDictionary *theDictionary in self.iconSet) {

        for (NSString *key in theDictionary) {
            NSString *value = [theDictionary objectForKey:key];
            NSRange stringRange = [value rangeOfString:searchText options:NSCaseInsensitiveSearch];

            if (stringRange.location != NSNotFound) {
                [filteredList addObject:theDictionary];
                break;
            }
        }
    }
}
[myTableView reloadData];
}

xCode 没有向我发出任何错误或警告，但当我按下搜索栏中的字母或图标时，应用程序崩溃，并显示以下消息:

*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[__NSCFConstantString countByEnumeratingWithState:objects:count:]: unrecognized selector sent to instance 0x1000f94d0'

我尝试在 stackoverflow 上查找它，但没有找到我要找的答案。我希望这里有人可以帮助我找到我的(可能是愚蠢的)错误。

Answer 1

因为 self.iconSet 是一个字典，用 for..in 迭代它会给你字符串形式的键。因此，不需要第二个循环:

for (NSString *key in self.iconSet) {
    NSString *value = [self.iconSet objectForKey:key];
    ...
}

或更好:

[self.iconSet enumerateKeysAndObjectsUsingBlock:^(NSString *key, NSString *value, BOOL *stop) {
     ...
}]