ios - 如何将迭代的字符串值结果集转换为ios中的数组？

Question

我希望得到如下结果:

set arr[0]=jan23,2016 …… upto arr[6] =jan29,2016.

为此，我有以下代码:

// To get future or next 6 days from now or current date
NSCalendar * calendar = [NSCalendar autoupdatingCurrentCalendar];
NSDateComponents * datecomponents = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDayfromDate:[NSDate date]];
for(int i=0;i<6;++i)
{
    NSDate * todaydate = [calendar dateFromComponents:datecomponents];
    NSLog(@"%@",todaydate);
    ++datecomponents.day;
    NSDateFormatter * dateformatter = [[NSDateFormatter alloc]init];
    [dateformatter setDateStyle:NSDateFormatterMediumStyle];
    NSString * convertedstring = [dateformatter stringFromDate:todaydate];
    NSLog(@“converteddate:%@",convertedstring);

为此，我收到了如下回复:

converteddate:Jan 23, 2016 similarly upto jan29,2016

然后我这样做:

NSMutableString * newstring = [[NSMutableString alloc]init];
[newstring stringByAppendingString:convertedstring];
NSLog(@"%@",newstring);

还有这样的:

    NSMutableArray * arrdata;
    arrdata = [[NSMutableArray alloc]init];
    [arrdata addObject:convertedstring];
    NSLog(@"%@",arrdata);
}

如何得到上面的结果集。字符串迭代后如何将它们转换成数组。

Answer 1

数组必须在 for 循环之外声明和分配，因为您每次迭代都会重置它:

NSMutableArray * arrdata = [[NSMutableArray alloc]init];
NSCalendar * calendar = [NSCalendar autoupdatingCurrentCalendar];
NSDateComponents * datecomponents = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDayfromDate:[NSDate date]];
for(int i=0;i<6;++i)

也没有必要这样做，因为你永远不会真正使用 newstring :

NSMutableString * newstring = [[NSMutableString alloc]init];
[newstring stringByAppendingString:convertedstring];