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php - Mysql查询按月存储员工考勤

转载 作者:行者123 更新时间:2023-11-29 11:54:09 25 4
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如何在mysql数据库中插入所有员工出勤情况(每月一次)这是我的数据库表

att_employee_id | att_year | att_month | att_present_days | att_absent_days |   att_workingdays

Date.prototype.daysInThisMonthOfThisYear=function() {
return new Date(this.getFullYear(),this.getMonth()+1,0).getDate();
}
var days_inmonth = new Date().daysInThisMonthOfThisYear();

$(document).ready(function() {
$( ".absent_days" ).keyup(function() {
var days = $(this).val();
$(this).closest("tr").find(".present_days" ).val( days_inmonth - days );
})
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<form name="emp_att" action="" method="post">
<table>
<thead>
<tr>
<th class="head0" style="width:5%">S.No</th>
<th class="head1" style="width:15%">Employee ID</th>
<th class="head0 no-sort" style="width:15%">No.of days present</th>
<th class="head1 no-sort" style="width:15%">No.of days absent</th>
</tr>
</thead>
<tbody>
<tr>
<td>1</td>
<td>ETO0001</td>
<td><input type="text" class="present_days" name="present_days" value=""></td>
<td><input type="number" name="absent_days" class="absent_days" min="0" max="<?php echo date('t'); ?>" onChange="absentdays()" style="width:100%"></td>
</tr>
<tr>
<td>2</td>
<td>ETO0002</td>
<td><input type="text" class="present_days" name="present_days" value=""></td>
<td><input type="number" name="absent_days" class="absent_days" min="0" max="<?php echo date('t'); ?>" onChange="absentdays()" style="width:100%"></td>
</tr>
<tr>
<td>3</td>
<td>ETO0003</td>
<td><input type="text" class="present_days" name="present_days" value=""></td>
<td><input type="number" name="absent_days" class="absent_days" min="0" max="<?php echo date('t'); ?>" onChange="absentdays()" style="width:100%"></td>
</tr>
<tr>
<td>4</td>
<td>ETO0004</td>
<td><input type="text" class="present_days" name="present_days" value="" readonly></td>
<td><input type="number" name="absent_days" class="absent_days" min="0" max="<?php echo date('t'); ?>" onChange="absentdays()" style="width:100%"></td>
</tr>
</tbody>
</table>
<input type="submit" name="submit" value="Submit">
</form>

这是我获取所有员工的查询

   <form name="emp_att" action="" method="post">
<table>
<thead>
<tr>
<th class="head0" style="width:5%">S.No</th>
<th class="head1" style="width:15%">Employee ID</th>
<th class="head0 no-sort" style="width:15%">No.of days present</th>
<th class="head1 no-sort" style="width:15%">No.of days absent</th>
</tr>
</thead>
<tbody>
<?php
$allemp= mysqli_query($con,"select * from t_emp e");
$all_emp = mysqli_num_rows($allemp);

if ($all_emp > 0)
{
$i=1;
while($all_emp = mysqli_fetch_assoc($allemp))
{
echo "<tr>";
echo "<td>".$i."<input type='hidden' name='serialno' value='".$i++."'></td>
<td> ".$all_emp["emp_id"]."</td>
<td><input type='text' class='present_days' name='present_days' value=''></td>";
echo "<td><input type='number' name='absent_days' class='absent_days' min='0' max= date('t') onChange='absentdays()' style='width:100%'></a></td>";
echo "</tr>";
}
}
else
{
echo "0 Results";
}
?>
</tbody>
</table>
<input type="submit" name="submit" value="Submit">
</form>

在这里,我得到了上面表格中的所有 n 名员工。当输入所有员工“缺席天数”然后点击提交时,我只能将最后一条记录发送到数据库。谁能帮我将所有员工的出勤情况发送到数据库这是我的表单提交查询

<?php
if(isset($_POST['submit']))
{
$serialno=$_post['serialno'];
$employee_id=$_post['emp_id'];
$att_year = date('Y');
$att_month = date('m');
for($i=1; $i<= $serialno;$i++)
{
$present_days=$_POST['present_days'];
$absent_days=$_POST['absent_days'];
}
$query=mysqli_query($con,"INSERT INTO t_emp_attendance(att_employee_id,att_year,att_month,att_present_days,att_absent_days)values('$employee_id','$att_year','$att_month','$present_days','$absent_days')");
}
?>

任何建议将不胜感激,我需要将所有员工的出勤存储到数据库

最佳答案

检查输入字段的名称是否已创建。它可能会被最新值覆盖。将其作为数组格式发送,如“absent_days[]”,它将解决您的问题

关于php - Mysql查询按月存储员工考勤,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33492613/

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