sql - postgres 中的 connect_by_root 等价物

Question

我如何在 postgres 中隐藏 oracle 的 connect_by_root 查询。例如:这是一个 oracle 查询。

select fg_id, connect_by_root fg_id as fg_classifier_id
from fg
start with parent_fg_id is null
connect by prior fg_id = parent_fg_id 

Answer 1

您将使用一个递归公用表表达式，它简单地“承载”递归级别的根:

with recursive fg_tree as (
  select fg_id, 
         fg_id as fg_clasifier_id -- <<< this is the "root" 
  from fg
  where parent_fg_id is null -- <<< this is the "start with" part
  union all
  select c.fg_id, 
         p.fg_clasifier_id
  from fg c 
    join fg_tree p on p.fg_id = c.parent_fg_id -- <<< this is the "connect by" part
) 
select *
from fg_tree;

手册中有关递归公用表表达式的更多详细信息:http://www.postgresql.org/docs/current/static/queries-with.html