ios - 按数组之一的顺序对两个数组进行排序 [Swift 3.0 - Xcode 8]

Question

var ArrayToShowInTable = [String]()

我有两个数组:

let list = ["Carrot", "Apple", "Toothbrush", "Pear", "Oranges"]
let price = [3.50, 2.50, 1.50, 3.25, 4.25]

我想按价格(从小到大)对这两个数组进行排序，所以我得到类似的东西:

list = ["Toothbrush", "Apple", "Pear", "Carrot", "Oranges"]
price = [1.50, 2.50, 3.25, 3.50, 4.25]

所以我可以让他们加入他们

for i in 0...list.count-1{
let join = list[i] += "\(price[i])"
ArrayToShowInTable.append(join)
}

然后在TableView中呈现

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    return (ArrayToShowInTable.count)
}


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = UITableViewCell(style: UITableViewCellStyle.default, reuseIdentifier: "TableCell")
        cell.textLabel?.text = ArrayToShowInTable[indexPath.row] as? String
    return (cell)

有没有办法做到这一点？也许使用结构并打印到表？

请帮忙??

Answer 1

创建 Dictionary 以匹配 Products 和 Prices。处理数组很难处理。

let product = ["Carrot" : 3.50, "Apple" : 2.50, "Toothbrush" : 1.50, "Pear" : 3.25, "Oranges" : 4.25]


var sortedItem = product.sorted { ( first : (key: String, value: Double), second:(key: String, value: Double)) -> Bool in
    return first.value < second.value
}

var productList = [String]()
var priceList =  [Double]()

for (key, value) in sortedItem  {
    productList.append(key)
    priceList.append(value)
}

print(productList)
print(priceList)