mysql - 使用函数 FOUND_ROWS() 时出现连接给出错误结果的问题

Question

这是我的查询。

SELECT SQL_CALC_FOUND_ROWS (FOUND_ROWS() ) as total, 
(SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization 
WHERE dsp.profileid = pm.id and 
(dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec , 
pm.id as profileid, pm.loginid as loginid, dam.clinicname, dam.area, dam.address, dam.pincode, dam.id as 
addressid, dam.feecharge as feecharge, pm.fname, pm.lname, pm.email, pm.mobile, pm.phone, pm.gender, pm.dob, 
pm.totexp, pm.imagepath, pm.languages, pm.statement, pm.createdby, um.profile_url, um.clinic_url,
pm.hsbit,  (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm LEFT JOIN DAddress_Master dam on dam.profileid = pm.id left join Unique_Url_Master um on 
um.clinicid =dam.id WHERE dam.city='Surat' and pm.id IN (SELECT profileid FROM DSpecialization_Master 
WHERE specialization = (select id from Specialization_master where specialization='Dentist')) ORDER BY pm.id limit 0 , 10 

接受的结果是total:344，表明我得到total:1。

我已经执行了这个查询，并且得到了正确的结果。

select SQL_CALC_FOUND_ROWS id,(FOUND_ROWS() ) as total from unique_url_master1 limit 10;

总计:1313

我做错了什么？仅供引用，我无法中断查询，即首先执行

select SQL_CALC_FOUND_ROWS

并执行

select FOUND_ROWS()

非常需要帮助..

编辑

我更改了查询并使用 count(*) 函数。现在我得到了正确的 total:344 但它只返回一行。现在有人可以指导我吗？

SELECT  count(*) as total_count ,
        (SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization WHERE dsp.profileid = pm.id and (dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec, 
        pm.id as profileid, 
        pm.loginid as loginid, 
        dam.clinicname, 
        dam.area, 
        dam.address, 
        dam.pincode, 
        dam.id as addressid, 
        dam.feecharge as feecharge, 
        pm.fname, 
        pm.lname, 
        pm.email, 
        pm.mobile, 
        pm.phone, 
        pm.gender, 
        pm.dob, 
        pm.totexp, 
        pm.imagepath, 
        pm.languages, 
        pm.statement, 
        pm.createdby, 
        um.profile_url, 
        um.clinic_url, 
        pm.hsbit,  
        (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10;

我已经使用 COUNT(*) OVER() 在 MSSQL 中进行查询，由于需求更改，我必须将 MSSQL 查询转换为 MYSQl。结果我接受这样的

Answer 1

您使用的聚合函数COUNT没有n GROUP BY，这将始终生成一行。 Definition of GROUP BY 。

最好只使用 2 个单独的查询来获得您想要的结果，其中一个查询选择所有其他变量，而在一个查询中仅选择计数

所有行+变量

SELECT  (SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization WHERE dsp.profileid = pm.id and (dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec, 
    pm.id as profileid, 
    pm.loginid as loginid, 
    dam.clinicname, 
    dam.area, 
    dam.address, 
    dam.pincode, 
    dam.id as addressid, 
    dam.feecharge as feecharge, 
    pm.fname, 
    pm.lname, 
    pm.email, 
    pm.mobile, 
    pm.phone, 
    pm.gender, 
    pm.dob, 
    pm.totexp, 
    pm.imagepath, 
    pm.languages, 
    pm.statement, 
    pm.createdby, 
    um.profile_url, 
    um.clinic_url, 
    pm.hsbit,  
    (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10;

计数:

SELECT  count(*) as total_count,
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10;

如果您确实希望它像一次查询中的图像一样，则必须执行以下操作:

SELECT T1.overall_count, T2.*
FROM (SELECT COUNT(*) AS overall_count
    FROM Profile_Master pm 
    LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
    LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
    WHERE dam.city='Surat' 
    AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
    ORDER BY pm.id 
    LIMIT 0, 10) AS T1
JOIN ((SELECT GROUP_CONCAT(sp.specialization) FROM DSpecialization_Master dsp LEFT JOIN Specialization_Master sp on sp.id = dsp.specialization WHERE dsp.profileid = pm.id and (dsp.specialization = (select id from Specialization_master where specialization='Dentist' ))) as drspec, 
    pm.id as profileid, 
    pm.loginid as loginid, 
    dam.clinicname, 
    dam.area, 
    dam.address, 
    dam.pincode, 
    dam.id as addressid, 
    dam.feecharge as feecharge, 
    pm.fname, 
    pm.lname, 
    pm.email, 
    pm.mobile, 
    pm.phone, 
    pm.gender, 
    pm.dob, 
    pm.totexp, 
    pm.imagepath, 
    pm.languages, 
    pm.statement, 
    pm.createdby, 
    um.profile_url, 
    um.clinic_url, 
    pm.hsbit,  
    (SELECT GROUP_CONCAT(education) FROM DEducation_Master WHERE profileid = pm.id ) as dredu 
FROM Profile_Master pm 
LEFT JOIN DAddress_Master dam on dam.profileid = pm.id 
LEFT JOIN Unique_Url_Master um on um.clinicid =dam.id 
WHERE dam.city='Surat' 
AND pm.id IN (SELECT profileid FROM DSpecialization_Master WHERE specialization = (select id from Specialization_master where specialization='Dentist')) 
ORDER BY pm.id 
LIMIT 0, 10) AS T2