php - 选择下拉列表中选择的名称

Question

查询从God表中选择God

$sth =$dbh->prepare("SELECT god_id,god_name_ml,god_name_en,image,info_ml,info_en,details_ml,
       details_en,rounds_ml,rounds_en,mantra_ml,mantra_en,display_order FROM god");
       $sth->execute();

从神表中查询选择神。这里god_id是神表中的外键

   $stmt = $dbh->prepare("SELECT deity_id,god_id,deity_name_ml,deity_name_en,info_ml,info_en,details_ml,
      details_en,mantra_ml,mantra_en,display_order FROM deity
      WHERE deity_id = :deity_id");
    $stmt->bindValue(':deity_id',$deity_id,PDO::PARAM_INT);
    $stmt->execute();
    $result = $stmt->fetchAll();
    $temp_array=$result[0];
    $god_id=$temp_array['god_id'];

显示用于在上帝表的下拉列表中显示上帝的代码

<?php while ($row = $sth->fetch(PDO::FETCH_ASSOC)) { ?>
       <option value="<?php echo $row['god_id'];?>">
         <?php echo $row['god_name_en']; ?>
       </option>
       <?php } ?>
       </option>
   </select>

我需要的是，在下拉列表中，神表中给定的 god_id 存在于神表中，使其被选中。我只需要选择 ID 即可

Answer 1

只需检查两个 id 是否相同，试试这个:

<?php while ($row = $sth->fetch(PDO::FETCH_ASSOC)) { ?>
  <option <?php if($row['god_id'] == $god_id) { echo "selected='selected'"; } ?> value="<?php echo $row['god_id'];?>"><?php echo $row['god_name_en']; ?></option>
<?php } ?>
</option>
</select>