java - 如何在appium Java IOS中上下左右滑动

Question

.moveTo()//显示此错误:未定义类型 WaitOptions 的方法 moveTo(PointOption)。

我执行提供的快速修复，即:将强制转换添加到方法接收器

以下错误显示:TouchAction 类型中的方法 waitAction(WaitOptions) 不适用于参数 (TouchAction)

Java 版本“1.8.0_191”模拟器 - iPhone x (IOS 12)应用程序 1.9.0

public static void swipe(MobileDriver driver, DIRECTION direction, long duration) {
    org.openqa.selenium.Dimension size = driver.manage().window().getSize();

    int startX = 0;
    int endX = 0;
    int startY = 0;
    int endY = 0;

    switch (direction) {
        case RIGHT:
            startY = (int) (size.height / 2);
            startX = (int) (size.width * 0.90);
            endX = (int) (size.width * 0.05);
            TouchAction action = new TouchAction(driver);
            action.press(PointOption.point(427, 878))
            .waitAction(WaitOptions
                    .waitOptions(Duration
                            .ofMillis(1300))
                    .moveTo(PointOption.point(427, 554))
                    .release().perform();

            break;

        case LEFT:
            startY = (int) (size.height / 2);
            startX = (int) (size.width * 0.05);
            endX = (int) (size.width * 0.90);
            new TouchAction(driver)
                    .press(startX, startY)
                    .waitAction(Duration.ofMillis(duration))
                    .moveTo(endX, startY)
                    .release()
                    .perform();

            break;

        case UP:
            endY = (int) (size.height * 0.70);
            startY = (int) (size.height * 0.30);
            startX = (size.width / 2);
            new TouchAction(driver)
                    .press(startX, startY)
                    .waitAction(Duration.ofMillis(duration))
                    .moveTo(endX, startY)
                    .release()
                    .perform();
            break;


        case DOWN:
            startY = (int) (size.height * 0.70);
            endY = (int) (size.height * 0.30);
            startX = (size.width / 2);
            new TouchAction(driver)
                    .press(startX, startY)
                    .waitAction(Duration.ofMillis(duration))
                    .moveTo(startX, endY)
                    .release()
                    .perform();

            break;

    }
}

如果使用

公共(public)枚举方向{左}

我希望它向左滑动

Answer 1

waitAction 方法不接受 java.time.Duration 持续时间 它必须使用 waitOptions 传递，就像您在 中使用的那样正确的 案例。检查 waitOptions 详细信息 here

同样moveTo和press接受PointOptions，不能直接传递坐标。

    case LEFT:
        startY = (int) (size.height / 2);
       startX = (int) (size.width * 0.05);
        endX = (int) (size.width * 0.90);
        new TouchAction(driver)
                .press(PointOption.point(startX, startY))
                .waitAction(WaitOptions
                .waitOptions(Duration
                        .ofMillis(duration))
                .moveTo(PointOption.point(endX, startY))
                .release()
                .perform();