gpt4 book ai didi

postgresql - PostgreSQL 中固定大小 JSONB 数组的聚合

转载 作者:行者123 更新时间:2023-11-29 11:25:11 27 4
gpt4 key购买 nike

我正在努力对 PostgreSQL 数据库中的 JSONB 字段进行聚合。这可能用一个例子更容易解释,所以如果创建并填充一个名为 analysis 的表,其中包含 2 列(idanalysis),如下所示:-

create table analysis (
id serial primary key,
analysis jsonb
);

insert into analysis
(id, analysis) values
(1, '{"category" : "news", "results" : [1, 2, 3, 4, 5 , 6, 7, 8, 9, 10, 11, 12, 13, 14, null, null]}'),
(2, '{"category" : "news", "results" : [11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, null, 26]}'),
(3, '{"category" : "news", "results" : [31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46]}'),
(4, '{"category" : "sport", "results" : [51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66]}'),
(5, '{"category" : "sport", "results" : [71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86]}'),
(6, '{"category" : "weather", "results" : [91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106]}');

如您所见,analysis JSONB 字段始终包含 2 个属性 categoryresults。结果属性将始终包含一个大小为 16 的固定长度数组。我使用了各种函数,例如 jsonb_array_elements 但我正在尝试执行以下操作:-

  1. 按分析分组->'类别'
  2. 每个数组元素的平均值

当我想要一个语句返回按类别分组的 3 行(即 newssportweather)和 16 个固定长度包含平均值的数组。更复杂的是,如果数组中有 null,那么我们应该忽略它们(即我们不是简单地按行数求和和平均)。结果应如下所示:-

 category  | analysis_average
-----------+--------------------------------------------------------------------------------------------------------------
"news" | [14.33, 15.33, 16.33, 17.33, 18.33, 19.33, 20.33, 21.33, 22.33, 23.33, 24.33, 25.33, 26.33, 27.33, 45, 36]
"sport" | [61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76]
"weather" | [91, 92, 93, 94, 95, 96, 97, 98, 99, 00, 101, 102, 103, 104, 105, 106]

注意:注意第一行最后 2 个数组项中的 4536,这说明忽略了 nullss.

我考虑过创建一个将数组分解为 16 列的 View ,即

create view analysis_view as
select a.*,
(a.analysis->'results'->>0)::int as result0,
(a.analysis->'results'->>1)::int as result1
/* ... etc for all 16 array entries .. */
from analysis a;

这对我来说似乎非常不优雅,并且首先消除了使用数组的优势,但可能会使用这种方法将某些东西组合在一起。

如有任何指点或提示,我们将不胜感激!

性能在这里也很重要,所以性能越高越好!

最佳答案

这适用于任何长度的数组

select category, array_agg(average order by subscript) as average
from (
select
a.analysis->>'category' category,
subscript,
avg(v)::numeric(5,2) as average
from
analysis a,
lateral unnest(
array(select jsonb_array_elements_text(analysis->'results')::int)
) with ordinality s(v,subscript)
group by 1, 2
) s
group by category
;
category | average
----------+----------------------------------------------------------------------------------------------------------
news | {14.33,15.33,16.33,17.33,18.33,19.33,20.33,21.33,22.33,23.33,24.33,25.33,26.33,27.33,45.00,36.00}
sport | {61.00,62.00,63.00,64.00,65.00,66.00,67.00,68.00,69.00,70.00,71.00,72.00,73.00,74.00,75.00,76.00}
weather | {91.00,92.00,93.00,94.00,95.00,96.00,97.00,98.00,99.00,100.00,101.00,102.00,103.00,104.00,105.00,106.00}

table functions - with ordinality

lateral

关于postgresql - PostgreSQL 中固定大小 JSONB 数组的聚合,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35847467/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com