iphone - 调试程序收到信号 "SIGABRT"

Question

NSString *aName = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)];
NSString *aDescription = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)];
NSString *aImageUrl = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 3)];
NSString *aCount = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 4)];
Animal *animal = [[Animal alloc] initWithName:aName description:aDescription url:aImageUrl countc:aCount ];

程序在设置“*aCount”的行接收到信号“SIGABRT”，我该如何调试(解决)这种类型的错误？

Answer 1

似乎数据库列的值为空。在处理 sqlite 时，您需要先检查 null 后再使用。

做这样的事情 -

if ((char *)sqlite3_column_text(compiledStatement, 4))
{
    NSString *aCount = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 4)];

}