php - MySQL SUM 与分组日期

Question

如何获取带有分组日期的数据价格？

SELECT store.date, store.pic, owner.name, 
SUM (CASE WHEN [>>GROUPED store.date<<] THEN store.price) AS total_price
FROM store
JOIN owner 
ON store.pic = owner.name GROUP BY store.date

我想像这样显示:

+-------------+------+------------+
| date        | name |  price     | 
+-------------+------+------------+
| 2016-09-30  | John | 100000.00  |
| 2016-09-29  | Rey  | 125000.00  | 
+-------------+------+------------+

Answer 1

试试这个可能会对你有帮助，

 SELECT store.date, store.pic, owner.name,SUM(store.price) AS total_price
 FROM store
 JOIN OWNER ON store.pic = owner.name
 GROUP BY store.date

我不明白为什么你在查询中使用 case 语句