javascript - 如果在 JavaScript 中它是空对象，如何将最深对象更改为字符串值

Question

假设我有这个对象:

{CONN_INFO: {CFGSwitch: {412: {}}}}

它的深度为 4。我想将键 412 重新分配给 "{}"，这样最终的对象将是

{CONN_INFO: {CFGSwitch: {412: "{}"}}}

检查深度的函数:

function checkDepth(object) {
  var level = 1;
  var key;
  for(key in object) {
      if (!object.hasOwnProperty(key)) continue;

      if(typeof object[key] == 'object'){
          var depth = checkDepth(object[key]) + 1;
          level = Math.max(depth, level);
      }
  }
  return level;
}

我有这样的东西，但我不确定它是否是最佳的或者是否适用于所有情况。将不胜感激。

function checkIfLastLevelEmpty(obj, depth) {
  for (var key in obj) {
    var val = obj[key];
    if (Object.keys(obj[key]).length === 0) {
      obj[key] = "{}";
    }
    else {
      if (depth >0) {
        checkIfLastLevelEmpty(val, depth-1);
      }
    }
  }
}

Answer 1

首先让我们结合一些知识:

How do I test for an empty JavaScript object?

上面的问题有一个很棒的答案，里面有很多选项，我将编辑片段以形成几个函数:

function isObject (obj) {
    return obj.constructor === Object;
}

function isEmptyObject (obj) {    
    return Object.keys(obj).length === 0 && isObject(obj);
}

王牌。现在，假设你有一个非常线性的对象结构，它不是一个复杂的数组并且不关心深度(只关心它是空的)让一个函数在树中循环。

function convertEmptyObjects (obj, currentDepth) {
    currentDepth = currentDepth || 0;
    for (var key in obj) {
        var val = obj[key];
        if (isObject(val)) {
            if (isEmptyObject(val)) {
                obj[key] = "{}";
                console.log("Defeated boss ("+ key +") on level "+ currentDepth +"!");
            }else{
                convertDeepestEmptyObject (val, currentDepth + 1);                    
            }
        }
    }
    return obj;
}

让我们在一个看起来很糟糕的对象上测试一下:

var testObject = {
    CONN_INFO: {
        CFGSwitch: {
            412: {}, // Level 2
            413: {
                content: {}  // Level 3
            }
        },
        DummySwitch: {} // Level 1
    },
    TEST_CONN_INFO: {
        CFGSwitch: {
            414: {},  // Level 2
            415: {
                content: {
                    host: "google",
                    port: "8080",
                    protocol: {}  // Level 4
                }
            }
        }
    },
    STAGING_CONN_INFO: {} // Level 0
}

convertEmptyObjects(testObject);
JSON.stringify(testObject)

/* Output:
* Defeated boss (412) on level 2!
* Defeated boss (content) on level 3!
* Defeated boss (DummySwitch) on level 1!
* Defeated boss (414) on level 2!
* Defeated boss (protocol) on level 4!
* Defeated boss (STAGING_CONN_INFO) on level 0!
*/

// Result:
{
    "CONN_INFO": {
        "CFGSwitch": {
            "412": "{}", // Empty String {}
            "413": {
                "content": "{}" // Empty String {}
            }
        },
        "DummySwitch": "{}" // Empty String {}
    },
    "TEST_CONN_INFO": {
        "CFGSwitch": {
            "414": "{}", // Empty String {}
            "415": {
                "content": {
                    "host": "google",
                    "port": "8080",
                    "protocol": "{}" // Empty String {}
                }
            }
        }
    },
    "STAGING_CONN_INFO": "{}" // Empty String {}
}

给你。