javascript - 导入的异步函数不能正确解析数据

Question

背景:

我一直在使用 create-react-app 来创建 React 组件，我的最新项目需要一个服务器后端来返回数据。

我喜欢使用从“API”文件中导入的函数来模拟 API 返回的数据。

最近，我开始采用较新的 async/await 函数，主要是因为它们更易于阅读。

问题:

在我的一个组件中，我导入了这些 API 函数，我最初将它们创建为异步函数(据我所知，默认情况下，返回一个 promise 并将通过 return 解析值关键字并通过 throw 关键字拒绝。

但是，当我调试代码时，我看到它调用异步函数，然后立即继续控制未定义的“结果”，如果我使用 .then(res=>{ console.log(res)}); 不等待promise resolve，直接进入then回调函数。

**调用这些函数的代码:**

// I have removed all the other lines of code and left the important code
import { getVideoList } from './api';
runMe = async () => {
    let res = await getVideolist();
    console.log(res);
}
<button onClick={this.runMe}>Click Me</button>

问题在于，当使用 Promises 包装函数的内容并使用 Promises resolve 函数时，它可以正常工作。

原代码如下:

export let getVideoList = async () => {
    let random = Math.floor(Math.random() * 3000);
    setTimeout(() => {
        let res = [
            {
                video_ID: 3,
                video_url: 'https:google.com/3',
                video_description: 'A basic video of exercise',
                tags: ['upper-body', 'biceps', 'triceps'],
            },
            {
                video_ID: 2,
                video_url: 'https:google.com/2',
                video_description: 'A basic video of exercise',
                tags: ['upper-body', 'biceps', 'triceps'],
            },
            {
                video_ID: 1,
                video_url: 'https:google.com/1',
                video_description: 'A basic video of exercise',
                tags: ['upper-body', 'biceps', 'triceps'],
            },
        ];
        return res;
    }, random);
};
export let getTags = async () => {
    let random = Math.floor(Math.random() * 3000);
    setTimeout(() => {
        return [
            { tag_ID: 1, tagName: 'upper-body' },
            { tag_ID: 2, tagName: 'biceps' },
            { tag_ID: 3, tagName: 'triceps' },
            { tag_ID: 4, tagName: 'shoulders' },
        ];
    }, random);
};
export let getVideos = async () => {
    let random = Math.floor(Math.random() * 3000);
    setTimeout(() => {
        let res = [
            { video_ID: 3, video_url: 'https:google.com/3', video_description: 'A basic video of exercise' },
            { video_ID: 2, video_url: 'https:google.com/2', video_description: 'A basic video of exercise' },
            { video_ID: 1, video_url: 'https:google.com/1', video_description: 'A basic video of exercise' },
        ];
        return res;
    }, random);
};

这里是修改后的有效代码:

export let getVideoList = async () => {
    return new Promise((res, rej) => {
        let random = Math.floor(Math.random() * 3000);
        setTimeout(() => {
            res([
                {
                    video_ID: 3,
                    video_url: 'https:google.com/3',
                    video_description: 'A basic video of exercise',
                    tags: ['upper-body', 'biceps', 'triceps'],
                },
                {
                    video_ID: 2,
                    video_url: 'https:google.com/2',
                    video_description: 'A basic video of exercise',
                    tags: ['upper-body', 'biceps', 'triceps'],
                },
                {
                    video_ID: 1,
                    video_url: 'https:google.com/1',
                    video_description: 'A basic video of exercise',
                    tags: ['upper-body', 'biceps', 'triceps'],
                },
            ]);
            return res;
        }, random);
    });
};
export let getTags = async () => {
    return new Promise((res, rej) => {
        let random = Math.floor(Math.random() * 3000);
        setTimeout(() => {
            res([
                { tag_ID: 1, tagName: 'upper-body' },
                { tag_ID: 2, tagName: 'biceps' },
                { tag_ID: 3, tagName: 'triceps' },
                { tag_ID: 4, tagName: 'shoulders' },
            ]);
        }, random);
    });
};
export let getVideos = async () => {
    return new Promise((res, rej) => {
        let random = Math.floor(Math.random() * 3000);
        setTimeout(() => {
            res([
                { video_ID: 3, video_url: 'https:google.com/3', video_description: 'A basic video of exercise' },
                { video_ID: 2, video_url: 'https:google.com/2', video_description: 'A basic video of exercise' },
                { video_ID: 1, video_url: 'https:google.com/1', video_description: 'A basic video of exercise' },
            ]);
        }, random);
    });
};

我不确定为什么会这样，我已经尝试搜索并且只提出了使用异步导入的新主题。

虽然这对这个项目来说不是什么大问题，但我想在未来的项目中弄清楚这个问题。

修改代码以使用 async/await:

const timer = ms => new Promise(res => setTimeout(res, ms));
export let getVideoList = async () => {
    let random = Math.floor(Math.random() * 3000);
    await timer(random);
    let res = [
        {
            video_ID: 3,
            video_url: 'https:google.com/3',
            video_description: 'A basic video of exercise',
            tags: ['upper-body', 'biceps', 'triceps'],
        },
        {
            video_ID: 2,
            video_url: 'https:google.com/2',
            video_description: 'A basic video of exercise',
            tags: ['upper-body', 'biceps', 'triceps'],
        },
        {
            video_ID: 1,
            video_url: 'https:google.com/1',
            video_description: 'A basic video of exercise',
            tags: ['upper-body', 'biceps', 'triceps'],
        },
    ];
    return res;
};
export let getTags = async () => {
    let random = Math.floor(Math.random() * 3000);
    await timer(random);
    return [
        { tag_ID: 1, tagName: 'upper-body' },
        { tag_ID: 2, tagName: 'biceps' },
        { tag_ID: 3, tagName: 'triceps' },
        { tag_ID: 4, tagName: 'shoulders' },
    ];
};
export let getVideos = async () => {
    let random = Math.floor(Math.random() * 3000);
    await timer(random);
    let res = [
        { video_ID: 3, video_url: 'https:google.com/3', video_description: 'A basic video of exercise' },
        { video_ID: 2, video_url: 'https:google.com/2', video_description: 'A basic video of exercise' },
        { video_ID: 1, video_url: 'https:google.com/1', video_description: 'A basic video of exercise' },
    ];
    return res;
};

修复:

问题源于试图在 setTimeout 中返回一个值。

Answer 1

 await setTimeout(_=>{...},random)

不会工作，因为 setTimeout 不返回 promise 。可以 promise :

 const timer = ms => new Promise( res => setTimeout(res,ms));

所以你可以这样做

async whatever(){
  await timer(1000);
  return { ... };
}

(小提示:从超时内返回什么都不做...)