javascript - 在 JavaScript 中计算不包括周末和假期的天数

Question

我正在尝试编写一个代码，计算总天数，不包括周末和自定义假期。我搜索了 stackoverflow 和 adobe 论坛以找到解决方案并提供了以下代码。如果公众假期正好在工作日(周六至周三)，则不计入计算。我的问题是，如果公共(public)假期在周末(周四至周五)，则两者(假期和周末)都会扣除。假设休假持续时间为 18/09/2018-22/09/2018，总计数 2 天显示代替 3。同样对于 17/10/2018-21/10/2018，总计数 1 天显示代替3天。解决问题的任何帮助或任何想法都会很棒!问候

//Thursday and Friday will be excluded as weekend.
var start = this.getField("From").value;
// get the start date value
var end = this.getField("To").value;
var end = util.scand("dd/mm/yyyy H:MM:SS", end + " 0:00:00");
var start =util.scand("dd/mm/yyyy H:MM:SS", start + " 0:00:00");
event.value = dateDifference(start, end);
function dateDifference(start, end) {
  // Copy date objects so don't modify originals
  var s = new Date(+start);
  var e = new Date(+end);
  // Set time to midday to avoid daylight saving and browser quirks
  s.setHours(12,0,0,0);
  e.setHours(12,0,0,0);
  // Get the difference in whole days
  var totalDays = Math.round((e - s) / 8.64e7);
  // Get the difference in whole weeks
  var wholeWeeks = totalDays / 7 | 0;
  // Estimate business days as number of whole weeks * 5
  var days = wholeWeeks * 5;
  // If not even number of weeks, calc remaining weekend days
  if (totalDays % 7) {
    s.setDate(s.getDate() + wholeWeeks * 7);
    while (s < e) {
      s.setDate(s.getDate() + 1);
      // If day isn't a Thursday or Friday, add to business days
      if (s.getDay() != 4 && s.getDay() != 5) {
        ++days;
      }
    }
  }
var hdayar = ["2018/02/21","2018/03/17","2018/03/26","2018/04/14","2018/05/01","2018/08/15","2018/09/2 1","2018/10/18","2018/10/19","2018/12/16","2018/12/25"];
//test for public holidays
var phdays = 0;
for (var i = 0; i <hdayar.length; i++){
if ((Date.parse(hdayar[i]) >= Date.parse(start)) && (Date.parse(hdayar[i]) <= Date.parse(end))) {phdays ++;}}
  return days-phdays + 1;
}

Answer 1

您应该为此使用一个库，而不是重新发明轮子。

但是如果你想自己做，你可以使用 .getDay 来检查公共(public)假期是否在周末。

var weekend = [4, 5],   // for Thursday, Friday
    holDate, holDay;
for (var i = 0; i < hdayar.length; i++){
    holDate = Date.parse(hdayar[i]);
    holDay = new Date(holDate).getDay()
    if (weekend.indexOf(holDay) == -1 && holDate >= Date.parse(start) && holDate <= Date.parse(end)) {
        phdays ++;
    }
}

phdays 现在将包含范围内非周末公共(public)假期的数量。