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php - PDO::__construct(): MySQL 服务器已经消失

转载 作者:行者123 更新时间:2023-11-29 10:58:54 35 4
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这似乎是一个常见问题,我已经阅读了很多相关内容,尝试使用“ini_set”来更改超时,但仅 5 秒后仍然出现此错误。下面是我的代码示例,用于显示类之间的流程。

我最困惑的是它在 5 秒后抛出此警告(即使在页面刷新后),但它仍然从数据库中检索数据。

    require('../cfg/config.php');

class Process {

/**
* @var PDO
*/
private $conn = null;
/**
* @var PDOException
*/
public $error = null;
private $host = DB_SERVER;
private $user = DB_USER;
private $pass = DB_PASS;
private $db = DB_NAME;

public function __construct() {
ini_set('mysql.connect_timeout', 300);
ini_set('default_socket_timeout', 300);
$this->connect();
}

private function connect() {

$dsn = 'mysql:host=' . $this->host . ';dbname=' . $this->db;
$options = [
PDO::ATTR_PERSISTENT => true,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
];
try {
$this->conn = new PDO($dsn, $this->user, $this->pass, $options);
} catch(PDOException $e) {
$this->error = $e->getMessage();
}

return $this->conn;
}

public function query($sql, $params = null) {

preg_match('/SELECT/', $sql) ? $select = true : $select = false;

$connect = $this->conn->getAttribute(PDO::ATTR_CONNECTION_STATUS);

echo "CONNECTION STATUS::: " . $connect;

if($this->error == null) {

$query = $this->conn->prepare($sql);
$query->execute($params);

$query ? (!$select ? $results = true : $results = $query->fetchAll(PDO::FETCH_ASSOC))
: $results = false;
} else {
$results = $this->error;
}

return $results;
}


}

class Arrays {
public $family = [];
/**
* @var \Process
*/
private $db;

public function __construct() {

$this->db = new Process();

}
public function setFamily() {
$a = [];

$sql = "SELECT familyNick, familyName FROM budget.family ORDER BY familyOrder";
$query = $this->db->query($sql);

if($query != false && is_array($query)) {
foreach($query as $k => $v) {
$a[$v['familyNick']] = $v['familyName'];
}
}

$this->family = $a;
}
/**
* @return array
*/
public function getFamily() {

if(empty($this->family) || !isset($this->family)) {
$this->setFamily();
}

return $this->family;
}

}

class Options {

public $family = [];

/**
* @var \Arrays
*/
private $arrays;

public function __construct() {
$this->arrays = new Arrays();
}

public function setFamily() {

$this->family = $this->arrays->getFamily();
}
public function getFamilyOptions() {

if(empty($this->family)) {
$this->setFamily();
}

$options = [];

foreach($this->family as $famNick => $famName) {
$options[] = "<option class='family' value='$famNick'>" . $famName . "</option>";
}

return $options;

}


}


$test = new Options();

$family = $test->getFamilyOptions();

var_dump($family);

我确信这段代码存在各种设计缺陷。我现在只是担心 PDO 警告。

最佳答案

对于我试图完成的简单删除

ATTR_PERSISTENT => true

从选项数组中成功了!

关于php - PDO::__construct(): MySQL 服务器已经消失,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42584700/

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