javascript - 从数组中删除重复对象但合并嵌套对象

Question

当前有一个包含游戏版本的对象数组。然而，游戏发布可能发生在多个平台上，并且这些在数组中显示为单独的对象。我希望通过比较游戏 ID 来删除重复的游戏，但合并平台对象

我已经尝试使用 reduce 函数成功地删除了游戏 id 的重复对象，但我无法使它适应合并平台

const filteredArr = data.reduce((acc, current) => {
  const x = acc.find(item => item.game.id === current.game.id);

  if (!x) {
    return acc.concat([current]);
  } else {
    return acc;
  }
}, []);

当前数组:

const data = [{
  "id": 157283,
  "date": 1553212800,
  "game": {
    "id": 76882,
    "name": "Sekiro: Shadows Die Twice",
    "popularity": 41.39190295640344
  },
  "human": "2019-Mar-22",
  "m": 3,
  "platform": {"id": 48, "name": "PlayStation 4"},
  "region": 8,
  "y": 2019
}, {
  "id": 12,
  "date": 1553212800,
  "game": {
    "id": 76832,
    "name": "Spiderman",
    "popularity": 41.39190295640344
  },
  "human": "2019-Mar-22",
  "m": 3,
  "platform": {"id": 6, "name": "PC (Microsoft Windows)"},
  "region": 8,
  "y": 2019
}, {
  "id": 157283,
  "date": 1553212800,
  "game": {
    "id": 76882,
    "name": "Sekiro: Shadows Die Twice",
    "popularity": 41.39190295640344
  },
  "human": "2019-Mar-22",
  "m": 3,
  "platform": {"id": 48, "name": "Xbox"},
  "region": 8,
  "y": 2019
}]

合并后的预期格式:

[{
  "id": 157283,
  "date": 1553212800,
  "game": {
    "id": 76882,
    "name": "Sekiro: Shadows Die Twice",
    "popularity": 41.39190295640344
  },
  "human": "2019-Mar-22",
  "m": 3,
  "platforms": ["PlayStation", "Xbox"],
  "region": 8,
  "y": 2019
}, {
  "id": 12,
  "date": 1553212800,
  "game": {
    "id": 76832,
    "name": "Spiderman",
    "popularity": 41.39190295640344
  },
  "human": "2019-Mar-22",
  "m": 3,
  "platforms": ["Playstation"],
  "region": 8,
  "y": 2019
}]

Answer 1

你真的很接近，你只需要稍微改变一下逻辑。您可以尝试以下操作；一个例子 - https://repl.it/@EQuimper/ScaryBumpyCircle

const filteredArr = data.reduce((acc, current) => {
  const x = acc.find(item => item.game.id === current.game.id);

  if (!x) {
    current.platform = [current.platform]
    acc.push(current);
  } else {
    x.platform.push(current.platform);
  }

  return acc;
}, []);

返回值为

[
  {
    "id": 157283,
    "date": 1553212800,
    "game": {
      "id": 76882,
      "name": "Sekiro: Shadows Die Twice",
      "popularity": 41.39190295640344
    },
    "human": "2019-Mar-22",
    "m": 3,
    "platform": [
      {
        "id": 48,
        "name": "PlayStation 4"
      },
      {
        "id": 48,
        "name": "Xbox"
      }
    ],
    "region": 8,
    "y": 2019
  },
  {
    "id": 12,
    "date": 1553212800,
    "game": {
      "id": 76832,
      "name": "Spiderman",
      "popularity": 41.39190295640344
    },
    "human": "2019-Mar-22",
    "m": 3,
    "platform": [
      {
        "id": 6,
        "name": "PC (Microsoft Windows)"
      }
    ],
    "region": 8,
    "y": 2019
  }
]

如果您只想拥有一个平台字符串数组，请使用

const filteredArr = data.reduce((acc, current) => {
  const x = acc.find(item => item.game.id === current.game.id);

  if (!x) {
    current.platform = [current.platform.name]
    acc.push(current);
  } else {
    x.platform.push(current.platform.name);
  }

  return acc;
}, []);

现在返回值是

[
  {
    "id": 157283,
    "date": 1553212800,
    "game": {
      "id": 76882,
      "name": "Sekiro: Shadows Die Twice",
      "popularity": 41.39190295640344
    },
    "human": "2019-Mar-22",
    "m": 3,
    "platform": [
      "PlayStation 4",
      "Xbox"
    ],
    "region": 8,
    "y": 2019
  },
  {
    "id": 12,
    "date": 1553212800,
    "game": {
      "id": 76832,
      "name": "Spiderman",
      "popularity": 41.39190295640344
    },
    "human": "2019-Mar-22",
    "m": 3,
    "platform": [
      "PC (Microsoft Windows)"
    ],
    "region": 8,
    "y": 2019
  }
]