gpt4 book ai didi

mysql - 从已选择的表中选择数据

转载 作者:行者123 更新时间:2023-11-29 10:51:13 24 4
gpt4 key购买 nike

我有一些表正在尝试从中获取数据。我需要将 cust 和 emp 表链接到 sales 表。然后,依次从 person 表中获取 cust 和 emp 的姓名。

我被困住了

数据如下:

销售

+--------+--------+-------+-------+
| saleID | custID | empID | total |
|--------+--------+-------+-------|
| 1 | 1 | 1 | 3.00 |
|--------+--------+-------+-------|
| 2 | 2 | 3 | 6.00 |
|--------+--------+-------+-------|
| 3 | 3 | 1 | 9.00 |
|--------+--------+-------+-------|
| 4 | 2 | 2 | 2.00 |
|--------+--------+-------+-------|
| 5 | 3 | 3 | 1.00 |
|--------+--------+-------+-------+

客户

+--------+---------+----------+
| custID | company | personID
+--------+---------+----------+
| 1 | comp1 + 2 |
+--------+---------+----------+
| 2 | comp2 + 4 |
+--------+---------+----------+
| 3 | comp3 + 6 |
+--------+---------+----------+

emp

+--------+----------+----------+
| custID | username | personID |
+--------+----------+----------+
| 1 | emp1 | 1 |
+--------+----------+----------+
| 2 | emp2 | 3 |
+--------+----------+----------+
| 3 | emp3 | 5 |
+--------+----------+----------+

+----------+------+
| personID | name |
+----------+------+
| 1 | per1 |
+----------+------+
| 2 | per2 |
+----------+------+
| 3 | per3 |
+----------+------+
| 4 | per4 |
+----------+------+
| 5 | per5 |
+----------+------+
| 6 | per6 |
+----------+------+

我想查询给我这个:

+--------+--------+----------+-------+---------+-------+
| saleID | custID | custName | empID | empName | total |
+--------+--------+----------+-------+---------+-------+
| 1 | 1 | per2 | 1 | per1 | 3.00 |
+--------+--------+----------+-------+---------+-------+
| 2 | 2 | per4 | 3 | per5 | 6.00 |
+--------+--------+----------+-------+---------+-------+
| 3 | 3 | per6 | 1 | per1 | 9.00 |
+--------+--------+----------+-------+---------+-------+
| 4 | 2 | per4 | 2 | per3 | 2.00 |
+--------+--------+----------+-------+---------+-------+
| 5 | 3 | per6 | 3 | per5 | 1.00 |
+--------+--------+----------+-------+---------+-------+

最佳答案

简单的 JOIN 就可以解决问题:

SELECT 
a.saleID,
b.custID,
p1.name as custName,
c.empID,
p2.name as empName,
a.total
FROM SALES a
JOIN cust b
ON a.custID = b.custID
JOIN emp c
ON c.custID = a.custID AND c.empID = a.empID
JOIN person p1
ON p1.personID = b.personID
JOIN person p2
ON p2.personID = c.personID
ORDER BY saleID

关于mysql - 从已选择的表中选择数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43697999/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com