javascript - 如何使用 AngularJS $resource.query 传递参数？

Question

此刻，url localhost/view/titles 将使用下面的路由、 Controller 和服务，服务器将返回所有标题对象的列表。我如何扩展服务以允许额外的查询参数，例如结果限制等？

// main app module with route
var app = angular.module('app', ['ngResource']).
    config(function ($routeProvider, $locationProvider) {
        $routeProvider.when(
            '/view/:obj/:limit',
            {
                templateUrl: '/static/templates/titles.html',
                controller: 'titlesController'
            }
        )})

// list service
var listService = app.factory('listService', function ($q, $resource) {
        return {
            getList: function (obj) {
                var deferred = $q.defer();

                $resource('/api/view/' + obj).query(
                    function (response) {
                        console.log('good')
                        deferred.resolve(response);
                    }
                    ,
                    function (response) {
                        console.log('bad ' + response.status)
                        deferred.reject(response);
                    }
                )
                return deferred.promise;
            }
        }
    }
)


// controller
var titlesController = bang.controller('titlesController', function($scope, listService, $routeParams){
    $scope.titles = listService.getList($routeParams.obj);
})

Answer 1

示例代码如下:

angular.module('phonecatServices', ['ngResource']).
    factory('Phone', function($resource){
  return $resource('phones/:phoneId.json', {}, {
    query: {method:'GET', params:{phoneId:'phones'}, isArray:true}
  });
});