mysql - 外键和mysql与hibernate

Question

我正在使用 Hibernate 在 mySql 数据库中创建表。我有两张表“conge”和“employee”，并且我有一个多对一的关系。 “conge”表有一个员工 ID 的外键。

我注意到在我的表“conge”中插入两行后，我遇到了外键问题。我已经使用 hibernate 和 phpmyadmin 来插入，并且在插入两行后总是遇到同样的问题。

这是我的错误

无法添加或更新子行:外键约束失败 (concretepage.Conge, CONSTRAINT FKk1p9i6bbic92cgaad05k4smsg FOREIGN KEY ( id)引用员工(id))

谢谢

更新我已经导出了数据库，这是sql文件

-- phpMyAdmin SQL Dump
-- version 4.7.0
-- https://www.phpmyadmin.net/
--
-- Host: localhost
-- Generation Time: Jul 06, 2017 at 11:50 AM
-- Server version: 10.1.24-MariaDB
-- PHP Version: 7.1.6

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
SET AUTOCOMMIT = 0;
START TRANSACTION;
SET time_zone = "+00:00";


/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8mb4 */;

--
-- Database: `concretepage`
--

-- --------------------------------------------------------

--
-- Table structure for table `Conge`
--

CREATE TABLE `Conge` (
  `id` int(11) NOT NULL,
  `date` datetime DEFAULT CURRENT_TIMESTAMP,
  `dateDebut` date DEFAULT NULL,
  `dateFin` date DEFAULT NULL,
  `numero` int(11) NOT NULL,
  `status` varchar(255) DEFAULT NULL,
  `employe_id` int(11) DEFAULT NULL,
  `typeConge_id` int(11) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `Conge`
--

INSERT INTO `Conge` (`id`, `date`, `dateDebut`, `dateFin`, `numero`, `status`, `employe_id`, `typeConge_id`) VALUES
(1, '2017-07-06 10:46:30', NULL, NULL, 0, NULL, NULL, NULL),
(2, '2017-07-06 10:46:34', NULL, NULL, 0, NULL, NULL, NULL);

-- --------------------------------------------------------

--
-- Table structure for table `EMPLOYE`
--

CREATE TABLE `EMPLOYE` (
  `id` int(11) NOT NULL,
  `nom` varchar(255) DEFAULT NULL,
  `post_id` int(11) DEFAULT NULL,
  `userInfo_login` varchar(255) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `EMPLOYE`
--

INSERT INTO `EMPLOYE` (`id`, `nom`, `post_id`, `userInfo_login`) VALUES
(1, 'foulen', NULL, 'user'),
(2, 'falten', NULL, 'user');

-- --------------------------------------------------------

--
-- Table structure for table `POST`
--

CREATE TABLE `POST` (
  `id` int(11) NOT NULL,
  `code` varchar(255) DEFAULT NULL,
  `intituler` varchar(255) DEFAULT NULL,
  `employe_id` int(11) DEFAULT NULL,
  `id_superieur` int(11) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

-- --------------------------------------------------------

--
-- Table structure for table `TypeConge`
--

CREATE TABLE `TypeConge` (
  `id` int(11) NOT NULL,
  `code` int(11) NOT NULL,
  `intituler` varchar(255) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `TypeConge`
--

INSERT INTO `TypeConge` (`id`, `code`, `intituler`) VALUES
(1, 5757, 'Annuel'),
(2, 2, 'Maladie');

-- --------------------------------------------------------

--
-- Table structure for table `users`
--

CREATE TABLE `users` (
  `login` varchar(255) NOT NULL,
  `country` varchar(255) DEFAULT NULL,
  `enabled` smallint(6) DEFAULT NULL,
  `password` varchar(255) DEFAULT NULL,
  `role` varchar(255) DEFAULT NULL,
  `employe_id` int(11) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `users`
--

INSERT INTO `users` (`login`, `country`, `enabled`, `password`, `role`, `employe_id`) VALUES
('admin', NULL, 1, '$2a$10$OlJFlkoM9/nCAK1DUhcE7OvitoDHDip8GuoDt5NrSqWgV5aP7tMeC', 'ROLE_ADMIN', NULL),
('user', NULL, 1, '$2a$10$OlJFlkoM9/nCAK1DUhcE7OvitoDHDip8GuoDt5NrSqWgV5aP7tMeC', 'ROLE_USER', 1);

--
-- Indexes for dumped tables
--

--
-- Indexes for table `Conge`
--
ALTER TABLE `Conge`
  ADD PRIMARY KEY (`id`),
  ADD KEY `FKov9s99mmo220hv4d8ppeobut` (`employe_id`),
  ADD KEY `FKocvumeoahniu5uvsjlwq5mvnp` (`typeConge_id`);

--
-- Indexes for table `EMPLOYE`
--
ALTER TABLE `EMPLOYE`
  ADD PRIMARY KEY (`id`),
  ADD KEY `FKpe9llqbqsni2xqg1vms2h716j` (`post_id`),
  ADD KEY `FKioxxmg7s2j18x2fo7ahnclmcd` (`userInfo_login`);

--
-- Indexes for table `POST`
--
ALTER TABLE `POST`
  ADD PRIMARY KEY (`id`),
  ADD KEY `FKl6st4h0ujkdiun27r7tak7t7n` (`employe_id`),
  ADD KEY `FK3x5ro8omrg46k9jaihue19o8q` (`id_superieur`);

--
-- Indexes for table `TypeConge`
--
ALTER TABLE `TypeConge`
  ADD PRIMARY KEY (`id`);

--
-- Indexes for table `users`
--
ALTER TABLE `users`
  ADD PRIMARY KEY (`login`),
  ADD KEY `FK82xfucsr861ymb3t5sp2hulo3` (`employe_id`);

--
-- AUTO_INCREMENT for dumped tables
--

--
-- AUTO_INCREMENT for table `Conge`
--
ALTER TABLE `Conge`
  MODIFY `id` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=4;
--
-- AUTO_INCREMENT for table `EMPLOYE`
--
ALTER TABLE `EMPLOYE`
  MODIFY `id` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=5;
--
-- AUTO_INCREMENT for table `POST`
--
ALTER TABLE `POST`
  MODIFY `id` int(11) NOT NULL AUTO_INCREMENT;
--
-- AUTO_INCREMENT for table `TypeConge`
--
ALTER TABLE `TypeConge`
  MODIFY `id` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=3;
--
-- Constraints for dumped tables
--

--
-- Constraints for table `Conge`
--
ALTER TABLE `Conge`
  ADD CONSTRAINT `FKk1p9i6bbic92cgaad05k4smsg` FOREIGN KEY (`id`) REFERENCES `EMPLOYE` (`id`),
  ADD CONSTRAINT `FKlm34pn7fv5rcolnjgjyjnuj9l` FOREIGN KEY (`id`) REFERENCES `TypeConge` (`id`),
  ADD CONSTRAINT `FKocvumeoahniu5uvsjlwq5mvnp` FOREIGN KEY (`typeConge_id`) REFERENCES `TypeConge` (`id`),
  ADD CONSTRAINT `FKov9s99mmo220hv4d8ppeobut` FOREIGN KEY (`employe_id`) REFERENCES `EMPLOYE` (`id`);

--
-- Constraints for table `EMPLOYE`
--
ALTER TABLE `EMPLOYE`
  ADD CONSTRAINT `FKioxxmg7s2j18x2fo7ahnclmcd` FOREIGN KEY (`userInfo_login`) REFERENCES `users` (`login`),
  ADD CONSTRAINT `FKpe9llqbqsni2xqg1vms2h716j` FOREIGN KEY (`post_id`) REFERENCES `POST` (`id`);

--
-- Constraints for table `POST`
--
ALTER TABLE `POST`
  ADD CONSTRAINT `FK3x5ro8omrg46k9jaihue19o8q` FOREIGN KEY (`id_superieur`) REFERENCES `POST` (`id`),
  ADD CONSTRAINT `FKl6st4h0ujkdiun27r7tak7t7n` FOREIGN KEY (`employe_id`) REFERENCES `EMPLOYE` (`id`);

--
-- Constraints for table `users`
--
ALTER TABLE `users`
  ADD CONSTRAINT `FK82xfucsr861ymb3t5sp2hulo3` FOREIGN KEY (`employe_id`) REFERENCES `EMPLOYE` (`id`);
COMMIT;

/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;

Answer 1

因为外键位于 ID 列而不是 employee_id ...看:FOREIGN KEY (id) REFERENCES EMPLOYE (id)) ...并且您只有员工表中的两行