mysql - 如何对 sql select 语句进行排序，以便正确显示排行榜？

Question

我在选择和分组下表时遇到问题。表“Igralci”如下所示:

----------------------------------------------
|ID|U_ID|st_tock|st_srecanj|st_nizov|st_gemov|
----------------------------------------------
|19| 17 |   6   |     3    |   6    |   72   |
----------------------------------------------
|11| 19 |  12   |     6    |   24   |   144  |
----------------------------------------------
|15| 18 |  12   |     6    |   26   |   72   |
----------------------------------------------

我想按以下方式对 id 进行排序:

1. First looks at st_tock (if st_tock is same) ->
2. Looks at st_srecanj (if st_srecanj is same) ->
3. Looks at st_nizov (if st_nizov is same) ->
4. Looks at st_gemov

我尝试过:

Select * from Igralci 
group by id, st_tock, st_srecanj, st_nizov, st_gemov
order by st_tock, st_srecanj, st_nizov, st_gemov;

想要的显示是(ID):

1. 15(与 11 相同的 st_tock 和 st_srecanj，但他有更多 st_nizov)
2. 11
3. 19

Answer 1

您需要将“DES”或“ASC”添加到您的 order by 子句中才能获得您想要的结果。根据您提供的输出，您需要按顺序在每列后面添加“描述”

Select * from Igralci 
group by id, st_tock, st_srecanj, st_nizov, st_gemov
order by st_tock desc, st_srecanj desc, st_nizov desc, st_gemov desc;