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javascript - 如何在 d3 js 中的曲线上绘制 svg 圆圈?

转载 作者:行者123 更新时间:2023-11-29 10:32:14 26 4
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我正在编写一个软件,我在其中绘制了一些并排放置的 svg 圆圈,用户可以调整位置,更改线坐标。想要的结果是这样的

enter image description here

现在圆圈设置了一个不正确的空间,使圆圈向左移动

enter image description here

代码

function curve(val){
var w = d3.select("#new_row_1").attr("width");

var
numLines = 1,
lineSpacing = 18,
parabDepth = -30;

var row_spacing = 18;

if(val == 0){
parabDepth = -18;
}
else if(val == 1){
parabDepth = 0;
}
else if(val == 2){
parabDepth = 20;
}
else if(val == 3){
parabDepth = 30;
}
else if(val == 4){
parabDepth = 40;
}
else if(val == 5){
parabDepth = 50;
// row_spacing = 18.41;
}
else if(val == 6){
// row_spacing = 18.5;
parabDepth = 60;
}
else if(val == 7){
// row_spacing = 18.6;
parabDepth = 70;
}
else if(val == 8){
// row_spacing = 18.62;
parabDepth = 80;
}
else if(val == 9){
parabDepth = 90;
}
else if(val == 10){
parabDepth = 100;
}
else if(val == 11){
parabDepth = 110;
}
else if(val == 12){
parabDepth = 120;
}
else if(val == 13){
parabDepth = 130;
}
else if(val == 14){
parabDepth = 140;
}
else if(val == 15){
parabDepth = 150;
row_spacing = 20;
}

width = w ;

var curveData = [];

curveData.push([0,0]);
curveData.push([width/3 * 1, lineSpacing + parabDepth ]);
curveData.push([width/3 * 2, lineSpacing + parabDepth ]);
curveData.push([width/3 * 3, 1]);

var line = d3.line()
.x(function(d) {
return d[0];
})
.y(function(d) {
return d[1] + 8;
})
.curve(d3.curveCardinal);

var svg = d3.select("#new_row_1").attr("height", (numLines * lineSpacing) + lineSpacing + parabDepth + row_spacing).attr("width", width);

var g = svg.selectAll(".line")
.data(d3.range(numLines))
.enter()
.append("g")
.attr("class", "line")
.attr("transform", function(d){
return "translate(7," + (d*lineSpacing) + ")";
});

var path = g.append("path")
.attr("d", line(curveData))
.style("fill", "none")
.style("stroke", "pink")
.style("stroke-width","4")
.each(function(){
var g = d3.select(this.parentNode),
self = d3.select(this),
pathLength = width;

g.selectAll("circle")
.data(d3.range(1, width, row_spacing))
.enter()
.append("circle")
.attr("transform", (d,i) => {
var p = this.getPointAtLength(d);
return "translate(" + p.x + "," + p.y + ")";
})
.attr("r", 7)
.style("fill", function(d,i){
if(i == quant_col2 - 1){
return "red";
}else if(i == quant_col2/2){
return "yellow";
}
else if(i == quant_col2 - 2){
return "green";
}
else{
return "white";
}
})
.attr("stroke","black")
.attr("stroke-width","1");
});
}

setTimeout(function(){
curve(1)
},2000)
<script src="https://d3js.org/d3.v4.min.js"></script>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<svg width="252" height="18" id="new_row_1" class="new_row" style="top: 150px; left: 302px; -webkit-tap-highlight-color: rgba(0, 0, 0, 0);"><g><circle cx="8" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="3" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">1</text></g><g><circle cx="26" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="21" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">2</text></g><g><circle cx="44" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="39" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">3</text></g><g><circle cx="62" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="57" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">4</text></g><g><circle cx="80" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="75" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">5</text></g><g><circle cx="98" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="93" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">6</text></g><g><circle cx="116" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="111" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">7</text></g><g><circle cx="134" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="129" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">8</text></g><g><circle cx="152" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="147" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">9</text></g><g><circle cx="170" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="165" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">10</text></g><g><circle cx="188" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="183" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">11</text></g><g><circle cx="206" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="201" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">12</text></g><g><circle cx="224" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="219" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">13</text></g><g><circle cx="242" cy="8" r="7" style="fill: white; stroke: black; stroke-width: 1;"></circle><text dx="237" dy="11" class="label" style="font-size: 10px; font-weight: 500; display: none;">14</text><g class="label" style="display: none;"><rect x="126" y="1" width="14" height="14" style="fill: black;"></rect><text dx="130" dy="11" style="font-size: 9px; font-weight: 400; fill: white;">A</text></g></g></svg>

该值将由用户控制,这意味着它会动态变化。我想通过生产线均匀地处理它们。怎么做到的?

最佳答案

您正在使用 getPointAtLength() 查找沿曲线一定距离处的点的 X、Y 坐标。显然这是错误的。您想找到给定 X 的 Y 坐标。

没有内置的 SVG 功能。你将不得不自己计算。为此,您需要贝塞尔方程的多项式形式,这并不简单。

由于您只制作抛物线,因此最好完全避免使用贝塞尔曲线,而只需使用普通的简单二次方程 (ax^2 + bx + c) 计算您的曲线.

另外:如果您决定坚持使用贝塞尔曲线,那么您真的应该使用二次贝塞尔曲线,而不是 cbic 曲线。二次贝塞尔曲线的特性是它们总是形成一条抛物线。

关于javascript - 如何在 d3 js 中的曲线上绘制 svg 圆圈?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43285901/

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