javascript - 从字符串生成 block

Question

before going to problem, i want to generate dynamically like

temp = word[i] for 2,

temp = word[i-1] + word [i] for 3,

temp = word[i-2] + word[i-1] + word [i] for 4

我用代码解释了我尝试过的东西

function produceTwoChArray(word) {
      var temp = "";
      var tempArr = [];

      for (var i = 0; i < word.length; i++) {
        temp += word[i];
        if (temp.length === 2) {
          tempArr.push(temp);
        }
        temp = word[i];
      }
      return tempArr;
    }
    produceTwoChArray("breaking")

以上代码将产生如下结果:

 ["br", "re", "ea", "ak", "ki", "in", "ng"]

所以在 for 循环中，如果我更改为以下代码以生成三个字母，则

    if (temp.length === 3) {
        tempArr.push(temp);
    }
    temp =  word[i-1] + word[i];

结果:

["bre", "rea", "eak", "aki", "kin", "ing"]

所以添加临时长度为 3、4 的 word[i-1]、word[i-2] 等等。

为了动态创建临时语句，我创建了这些函数

1)

function generateWordSequence(n) {
  var n = n - 2;
  var temp1 = [];
  for (var j = n; j >= 0; j--) {
    temp1.push("word[i - " + j + "]");
  }
  temp1 = temp1.join('+').toString();
  return temp1;
}

2)

function generateWordSequence(n, word) {
  var n = n - 2;
  var temp1 = "";
  for (var j = n; j >= 0; j--) {
    temp1 = temp1 + word[i - j];
  }
  return temp1;
}

但是上面的两个尝试都以字符串形式返回，所以它没有用。当我像这样在 produceTwoChArray fn 中调用上面的 fn 时

function produceTwoChArray(word, n) {
  var temp = "";
  var tempArr = [];
  var retVar = generateWordSequence(n, word);

  for (var i = 0; i < word.length; i++) {
    temp += word[i];
    if (temp.length === n) {
      tempArr.push(temp);
    }

    temp = retVar;

  }
  return tempArr;
}

当我尝试 produceTwochArray 本身的所有逻辑时，我也没有工作。

请帮帮我。

Answer 1

您可以采用带有映射部分字符串的双切片。

function part(string, count) {
    return [...string.slice(count - 1)].map((_, i) => string.slice(i, i + count));
}

console.log(part("breaking", 2));
console.log(part("breaking", 3));
console.log(part("breaking", 4));