javascript - JS中带有对象的递归函数

Question

我有一个数组，其中包含可能具有第 n 级深度的对象。

像这样:

const settings = [

    {path: '/templates/pictures.php', url: '/pictures', label: 'Pictures', component: 'tab', template: 'default'},
    {path: '/templates/post-article.php', url: '/user/:username', component: 'table', template: 'default', children:[
        {path: '/templates/post-article-highlights.php', url: '/user/:username/highlights', component: 'table', template: 'default', children:[
              {path: '/templates/post-article-highlights.php', url: '/user/:username/highlights', component: 'table', template: 'default'}  

        ]}  
    ]}

]

我只需要将“Url”属性和子属性(如果存在)推送到另一个数组，但要保留深度。

所以新数组应该是这样的:

const newArray = [

    {url: '/pictures'},
    {url: '/user/:username', children:[
        {url: '/user/:username/highlights', children:[
                {url: '/user/:username/highlights'} 
        ]}  
    ]}

]

你能帮帮我吗？

谢谢

Answer 1

你可以使用 destructuring assignment对于想要的键并使用 Array#map获取只有一个属性的新数组并使用 Object.assign通过检查子项来获取子项对象，如果存在，则通过函数的递归调用从子项中获取 url。

function getUrls(array) {
    return array.map(({ url, children }) =>
        Object.assign({ url }, children && { children: getUrls(children) }));
}

var settings = [{ path: '/templates/pictures.php', url: '/pictures', label: 'Pictures', component: 'tab', template: 'default' }, { path: '/templates/post-article.php', url: '/user/:username', component: 'table', template: 'default', children: [{ path: '/templates/post-article-highlights.php', url: '/user/:username/highlights', component: 'table', template: 'default', children: [{ path: '/templates/post-article-highlights.php', url: '/user/:username/highlights', component: 'table', template: 'default' }] }] }],
    urls = getUrls(settings);

console.log(urls);

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