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javascript - 传递对象时防止在 PureComponent 上重新渲染

转载 作者:行者123 更新时间:2023-11-29 10:26:35 38 4
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使用 PureComponents 时与功能组件相比,您的优势在于组件在父组件更新时并不总是呈现。它实际上仅在组件 Prop 发生变化时才会呈现,在此示例中仅当您更改输入时。

如何在不破坏使用此类组件的所有优势的情况下将对象传递给 PureComponent?

这是否意味着一旦你有了一个你希望它是对象类型的 Prop ,最好让你的组件发挥作用?

我添加了一个例子来说明我的意思...(可能你需要在新窗口中打开它,因为有很多不同的 child )

class TestPureComponent extends React.PureComponent {
render() {
return <div style={{border: '1px solid black'}}>{this.props.text} : {this.props.inputValue} {Math.random()} <button onClick={() => {this.props.dismissClicked()}}>Click me</button> </div>
}
}

function TestFunctionalComponent () {
return <div style={{border: '1px solid black'}}>I always update as I am a functional component {Math.random()}</div>
}

const hell = () => {console.log('Logs hello')}

class RenderExample extends React.Component {
constructor (props) {
super(props)
this.state = {clicked: false, inputValue: 'inputValue'}
this.onClick = this.onClick.bind(this)
this.doSomething = this.doSomething.bind(this)
}

onClick () {
this.setState({clicked: !this.state.clicked})
}

doSomething () {
console.log('helllllo')
}

heee = () => {
console.log('heeeee')
}

render () {
return <div>
<button onClick={this.onClick}>
Update state (forces re-render) {this.state.clicked && 'clicked'}
</button>
<input onChange={(e) => this.setState({inputValue: e.target.value})} type="text" value={this.state.inputValue}/>
<br/>
<br/>
<TestFunctionalComponent />
<br/>
<TestPureComponent dismissClicked={() => hell} inputValue={this.state.inputValue} text="If you click the button this will re-render, if you change the input this will re-render"/>
<br/>
<TestPureComponent text="If you click the button this will NOT re-render, if you change the input this will re-render" dismissClicked={this.doSomething} inputValue={this.state.inputValue}/>
<br/>
<TestPureComponent text="If you click the button this will NOT re-render, if you change the input this will re-render" dismissClicked={this.heee} inputValue={this.state.inputValue}/>
<br/>
<TestPureComponent text="If you click the button this will NOT re-render, if you change the input this will re-render" dismissClicked={hell} inputValue={this.state.inputValue}/>
<br/>
<TestPureComponent text="If you click the button this will NOT re-render, if you change the input this will re-render" dismissClicked={hell} inputValue={this.state.inputValue}/>
<br/><br/>
<div> we will now add an inline object to each component and now they all update</div>

<TestPureComponent dismissClicked={() => hell} inlineOBJ={{hello: 'world'}} inputValue={this.state.inputValue} text="If you click the button this will re-render, if you change the input this will re-render"/>
<br/>
<TestPureComponent text="If you click the button this will re-render, if you change the input this will re-render" inlineOBJ={{hello: 'world'}} dismissClicked={this.doSomething} inputValue={this.state.inputValue}/>
<br/>
<TestPureComponent text="If you click the button this will re-render, if you change the input this will re-render" inlineOBJ={{hello: 'world'}} dismissClicked={this.heee} inputValue={this.state.inputValue}/>
<br/>
<TestPureComponent text="If you click the button this will re-render, if you change the input this will re-render" inlineOBJ={{hello: 'world'}} dismissClicked={hell} inputValue={this.state.inputValue}/>
<br/>
<TestPureComponent text="If you click the button this will re-render, if you change the input this will re-render" inlineOBJ={{hello: 'world'}} dismissClicked={hell} inputValue={this.state.inputValue}/>
</div>
}
}

ReactDOM.render(<RenderExample />, document.getElementById('root'))
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>

<div id="root"></div>

我想要的是看看是否有一种 PureComponent 的方法,当有一个 OBJECT 作为 prop 传入时,它不会总是更新。

最佳答案

您必须将该对象存储在某处,以便它不会在每次重新渲染时生成。这也适用于在渲染期间生成的函数(dismissClicked={() => hell})。

函数应该在渲染函数之外,这样它们就不会像这样为每个渲染创建: dismissClicked={this.hell}

对于对象,只需将其保存在状态中即可。

您可以使用功能组件实现完全相同的效果。使用 memo 包裹组件以启用浅比较。

要防止在每次渲染时生成函数,请使用 useCallback 和 useState 来保存您传递给子级的对象,以便引用保持不变。

您可以使用 useEffect 轻松更新这些对象。

希望这对您有所帮助。快乐编码。

关于javascript - 传递对象时防止在 PureComponent 上重新渲染,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57705867/

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