ios - 重置定时器信号的最佳方法是什么？

Question

我需要每 5 分钟从服务器获取一次数据。如果我确实下拉刷新，还需要从服务器获取数据，并重置计时器。

下面的代码是现在的解决方案，看起来工作正常。只是想知道如何简化代码？ ReactiveCocoa 中可能有更好的方法？

    RACSignal* refreshSignal = [self.refreshControl rac_signalForControlEvents:UIControlEventValueChanged];
    self.timerSignal = [[RACSignal interval:300 onScheduler:[RACScheduler scheduler] withLeeway:2] takeUntil:refreshSignal];
    [self.timerSignal subscribeNext:^(id x) {
        NSLog(@"==========================");
        NSLog(@"[Timer1]");
        [self.viewModel performFetch];
    }];

    [refreshSignal subscribeNext:^(id x) {
        NSLog(@"==========================");
        NSLog(@"[Refresh]");
        [self.viewModel performFetch];
        self.timerSignal = [[RACSignal interval:300 onScheduler:[RACScheduler scheduler] withLeeway:2] takeUntil:refreshSignal];
        [self.timerSignal subscribeNext:^(id x) {
            NSLog(@"==========================");
            NSLog(@"[Timer2]");
            [self.viewModel performFetch];
        }];
    }];

Answer 1

我能想到的最干净的方法是使用 RACReplaySubject，发送 300 个 interval 信号，然后在每次触发 block 时切换到发送的最新信号.

self.timerSubject = [RACReplaySubject replaySubjectWithCapacity:1];
RACSignal * refreshSignal = [self.refreshControl rac_signalForControlEvents:UIControlEventValueChanged];
RACSignal * timeSignal = [RACSignal interval:300 onScheduler:[RACScheduler scheduler] withLeeway:2];
[self.timerSubject sendNext:timeSignal];

@weakify(self)
[[self.timerSubject.switchToLatest merge:refreshSignal] subscribeNext:^(id _) {
    @strongify(self)
    [self.viewModel performFetch];
}];

[refreshSignal subscribeNext:^(id _) {
    @strongify(self)
    [self.timerSubject sendNext:timeSignal];
}];