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Javascript - BackboneJS - Backbone.sync 覆盖 - YDN - 异步错误

转载 作者:行者123 更新时间:2023-11-29 10:18:29 24 4
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我正在尝试将 YDN 与 Backbone.sync() 结合使用,但我遇到了 « fetchAll » 函数的问题。

例如,我有这个 View

var UserListView = Backbone.View.extend({
el: ".page",


initialize: function() {
this.users = new UserCollection();
},

render: function() {
var that = this;
this.users.fetch({
success:function(users){
var template = _.template($('#user-list-template').html(), {users : users.models});
that.$el.html(template);
},
error: function(users){
console.log("error");
}
})
}
});

在 BackboneSync 中:

switch (method) {
case "read":
resp = model.id ? get(model) : all(model);
break;
case "create":
resp = save(model);
break;
case "update":
resp = save(model);
break;
case "delete":
resp = remove(model);
break;
}

function all(collection) {
db.values("users", null, 10).done(function(records) {
$.each(records, function(index, val) {
collection.add(records);
});
return collection;
});
};

我想你知道我被困在哪里。 db.values("users", null, 10).done({...});是异步方法,比如this.users.fetch({}),在这种情况下,它总是返回一个错误。

你知道如何处理它吗?

谢谢,

开23

最佳答案

已解决:

switch (method) {
case "read":
model.id ? get(model) : all(model);
break;
case "create":
resp = save(model);
break;
case "update":
resp = save(model);
break;
case "delete":
resp = remove(model);
break;
}

function all(collection) {
console.log("je rentre");
db.values("users", null, 10).done(function(records) {
options.success(records);
});
};

和 View :

var UserListView = Backbone.View.extend({
el: ".page",


initialize: function() {
this.users = new UserCollection();
},

render: function() {
var that = this;
this.users.fetch({
success:function(users){
console.log(users.models);
var template = _.template($('#user-list-template').html(), {users : users.models});
that.$el.html(template);
}
})
}
});

关于Javascript - BackboneJS - Backbone.sync 覆盖 - YDN - 异步错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16695544/

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