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mysql - SQL : i got an Ambiguous error

转载 作者:行者123 更新时间:2023-11-29 10:11:45 25 4
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select [CLIENT_SUIT_ID]
,[CLIENT_CODE]
,[CARD_ID]
,[EXPIRE_DATE]
,ROW_NUMBER()over(partition by CARD_ID order by CARD_ID ASC)
from [KSS_TMP].[dbo].[CLIENT_SUIT] as Tab1 JOIN
(SELECT CARD_ID FROM [KSS_TMP].[dbo].[CLIENT_SUIT]
where CLIENT_CODE NOT LIKE '080%' AND CARD_ID != '-'
GROUP BY CARD_ID
HAVING COUNT(CARD_ID) > 1 ) as Tab2 ON Tab1.CARD_ID = Tab2.CARD_ID

当我尝试执行此代码时,我得到一个“不明确的列名'CARD_ID'。我在这里做错了什么?

最佳答案

CARD_ID的每个选择上添加表名称,例如SELECT Tab1.CARD_ID FROM ...

关于mysql - SQL : i got an Ambiguous error,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50848875/

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