java - 矩形绘图java Swing GUI的问题

Question

我正在用 java 编写一个程序，它根据鼠标坐标在屏幕上绘制一个矩形。但是，我无法为该矩形获取正确的颜色。目标是在用户单击屏幕并选择颜色后绘制一个具有正确颜色的矩形。我尝试了案例场景，但无法使其正常工作。不工作的部分进行了评论。

import java.awt.*;
import javax.swing.*;
import javax.swing.event.*;
import java.awt.geom.*;
import java.awt.event.*;


public class test extends JFrame implements ActionListener, MouseListener, KeyListener {
    Shape box = new Rectangle2D.Float(10, 10, 10, 10);

    public test () {

        setSize(250,150);

        addMouseListener(this);
        addKeyListener(this);

        Color bgColor = new Color(125,125,125);
        setBackground(bgColor);

    }

    public static void main(String[] args) {
        java.awt.EventQueue.invokeLater(new Runnable() {
              public void run() {
                   test frame = new test();
                   frame.setVisible(true);
              }
        });
    }

    public void actionPerformed(ActionEvent ae) {

    }

    public void drawRectangle(int x, int y) {

        Graphics g = this.getGraphics();
        // KeyEvent e = this.getKeyChar();

        // switch (test.keyTyped()) {
        // case b: 
            g.drawRect(x, y, x, y);
            g.setColor(Color.BLUE);
            g.fillRect(x, y, 2, 2);
        // case r:
            // g.drawRect(x, y, x, y);
            // g.setColor(Color.RED);
            // g.fillRect(x, y, 2, 2);
        // case y:
            // g.drawRect(x, y, x, y);
            // g.setColor(Color.Yellow);
            // g.fillRect(x, y, 2, 2);
        // case g:
            // g.drawRect(x, y, x, y);
            // g.setColor(Color.GREEN);
            // g.fillRect(x, y, 2, 2);
            //}
    }

    int x, y;

    public void mouseClicked(MouseEvent e) {
        x = e.getX();
        y = e.getY();
        repaint();
    }

    public void keyTyped(KeyEvent e) {

        char c = e.getKeyChar();
        c = Character.toLowerCase(c);   
    }

    @Override
    public void paint(Graphics g) {

        g.setColor(Color.white);
        g.drawString("Click anywhere to draw a rectangle", 50, 250);
        g.drawString("Choose color by pressing the corresponding key on your keyboard: ", 50, 270);

        g.setColor(Color.blue);
        g.drawString("B: Blue ", 50, 285);
        g.setColor(Color.red);
        g.drawString("R: Red ", 95, 285);
        g.setColor(Color.yellow);
        g.drawString("Y: Yellow ", 140, 285);
        g.setColor(Color.green);
        g.drawString("G: Green ", 195, 285);


        drawRectangle(x, y);
    }

    public void mouseExited(MouseEvent e) {
        // TODO Auto-generated method stub
    }

    public void mousePressed(MouseEvent e) {
        // TODO Auto-generated method stub
    }

    public void mouseReleased(MouseEvent e) {
        // TODO Auto-generated method stub
    }

    public void mouseEntered(MouseEvent e) {
        // TODO Auto-generated method stub
    }

    public void keyPressed(KeyEvent e) {
        // TODO Auto-generated method stub  
    }

    public void keyReleased(KeyEvent e) {
        // TODO Auto-generated method stub      
    }   
}

Answer 1

你可以这样做:

HashMap<Integer, Color> colorsMap = new HashMap<>();
int selectedColor = Color.BLUE;
public test() {
    ....
    colorsMap.put(KeyEvent.VK_B, Color.BLUE);
    colorsMap.put(KeyEvent.VK_R, Color.RED);
    colorsMap.put(KeyEvent.VK_Y, Color.YELLOW);
    colorsMap.put(KeyEvent.VK_G, Color.GREEN);
    ....
}

public void drawRectangle(Graphics g, int x, int y) {
    g.setColor(selectedColor);
    g.fillRect(x, y, 2, 2);
}
@Override
public void paint(Graphics g) {
    ....
    drawRectangle(g, x, y);
    ....
}
public void keyPressed(KeyEvent e) {
    if(colorsMap.containsKey(e.getKeyCode())){
        selectedColor = colorsMap.get(e.getKeyCode());
    }
}