mysql - SQL中两个表的比较

Question

我想知道快照表中不存在哪种“类型”，但总是出错:-

Select  * FROM 
     (Select type from snapshot) AS A where date = CURDATE())
    LEFT JOIN
     (Select type from register) AS B
ON A.type=B.type
WHERE B.type IS NULL

有人可以帮我吗？

Answer 1

以下是有效查询的示例:

SELECT a.type 
  FROM snapshot a
  LEFT 
  JOIN register b
    ON b.type = a.type
 WHERE a.date = CURDATE()
   AND b.type IS NULL