php - 使用 mysql 和 PHP 创建嵌套 JSON

Question

所以，我一直在尝试创建一个嵌套的 JSON，其中的数据将来自 MYSQL。

在写了一个长查询后得到了这个SQL数据-

 +-------------+--------+-------+-------+
 | Type        | month  | Year  | Total | 
 +-------------+--------+-------+-------+
 | AR          | April  | 2018  | 23443 |
 +-------------+--------+-------+-------+
 | AP          | April  | 2018  | 11456 |
 +-------------+--------+-------+-------+
 | AR          | May    | 2018  | 26483 |
 +-------------+--------+-------+-------+
 | AR          | May    | 2018  | 14442 |
 +-------------+--------+-------+-------+

需要创建此 JSON -

    [
       {
        "categorie": "April 2018", 
         "values": [
             {
               "value": 23443, 
               "rate": "AR"
             }, 
             {
               "value": 11456, 
               "rate": "AP"
             }
          ]
       }, 
  .
  .
  .
  ]

从早上起我就一直在想这个问题，但没有解决。得到了这个答案 - 奥 git _a，但它使用来自 SQL 的 2 个查询来获取数据。

需要帮助创建将生成 JSON 的 PHP 文件。

include '../config/config.php';
if(isset($_GET['sub_cat_id']))
{
         $sub_cat_id = $_GET['sub_cat_id']; 
        $result = mysql_query("SELECT 'AR' as Type,month(DocumentDate) as PeriodM, year(DocumentDate) as PeriodY, sum(Amount) as Total from custledgerentry group by PeriodY,PeriodM union all select 'AP' as Type,month(DocumentDate) as PeriodM, year(DocumentDate) as PeriodY, sum(Amount) as Total from vendledgerentry group by PeriodY,PeriodM"); 
        $json_response = array();
        $i=1;
                        while ($row = mysql_fetch_array($result))
                        {
                        $row_array['categorie'] = $row['month'];        
                        $row_array['value'] = $row['question']; 



        echo json_encode($row_array);
}

Answer 1

当您使用要分组的值作为数组键时，这变得很简单:

$results = [];

foreach ($databaseResult as $row) {
    $category = "$row[month] $row[Year]";

    if (!isset($results[$category])) {
        $results[$category] = ['category' => $category, 'values' => []];
    }

    $results[$category]['values'][] = ['rate' => $row['Type'], 'value' => $row['Total']];
}

echo json_encode(array_values($results));