java - 摆脱android中的 "=="语法错误

Question

elseif(v == button2) 行给出了一个错误，指出“ token '==' 上的语法错误，删除此 token ”。我从这个网站的主题“Variable OnClick listener android”中得到了使用它的想法。谁能告诉我如何使用它？

这是我的代码:

    View.OnClickListener yourListener = new View.OnClickListener(){
        public void onClick(View v){
            if( v ==  button1){
                new AlertDialog.Builder(this)
                .setTitle("Paracettamol")
                .setMessage("This medicine is generally used to cure Fever")
                .setNeutralButton("OK", null)
                .show();}
            }
        elseif( v == button2){
            new AlertDialog.Builder(this)

        .setTitle("sertraline")
        .setMessage("This medicine is generally used to cure Head aches")
        .setNeutralButton("OK", null)
        .show();

        }



        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub

        }
        }  ; 
        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub

        }
        }

上面提到的问题的答案有如下代码:

Button btn1, btn2;
public void onCreate(Bundle b)
{
    // here you do normal things like assigning a
    // content view to the activity, initiate buttons, etc.

    // then you assign the same listener to both buttons
    btn1.setOnClickListener(yourListener);
    btn2.setOnClickListener(yourListener);
}

// declare a OnClickListener that will execute different actions
// depending on the view that was clicked
View.OnClickListener yourListener = new View.OnClickListener(){
    public void  onClick  (View  v){
        if( v == btn1 ){
            // do something 
        }
        elseif( v == btn1 ){
            // do another thing
        }
    }
};

Answer 1

你可能错过了 else 和 if 之间的空格 - "elseif( v == button2) "