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javascript - RxJS 检测 observable 何时被订阅

转载 作者:行者123 更新时间:2023-11-29 10:05:26 26 4
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我需要检测一个可观察对象 (observedEvents) 何时被订阅,然后再订阅另一个可观察对象 (triggerEvent)。我不想手动订阅 triggerEvent,但只有在 observedEvents 有订阅时订阅一次。

这是一些解释我正在寻找的代码:

// This just emits events
let emitting = new EventEmitter();

// This is the main Observable which someone else might
// have access to
let observedEvents = Rx.Observable.merge(
Rx.Observable.fromEvent(emitting, 'aba'),
Rx.Observable.fromEvent(emitting, 'bob')
)

// This trigger should get a subscription if observedEvents
// has one, i.e. when I subscribe to observedEvents
// that subscription activates this trigger

// I have made an attempt at this by calling skipUntil
// this however skips one event, but I don't want that
let triggerEvent = Rx.Observable.merge(
// these actions are things that can
// happen when the trigger is active
Rx.Observable.of('a').delay(200),
Rx.Observable.of('b').delay(400),
Rx.Observable.of('c').delay(600)
)
.skipUntil(observedEvents);

// Something else should be used to activate trigger
// I don't want to do this part manually
triggerEvent.subscribe(val => {
console.log(`Do something fancy with ${val}`);
});

//----------------------------------------------------
// Somewhere else in the code...
//----------------------------------------------------
observedEvents.subscribe(evt => {
console.log(`Some event: ${evt}`);
});
// At this point I want triggerEvent to become active
// because observedEvents has a subscription

setTimeout(() => {
emitting.emit('bob', 'world');
setTimeout(() => emitting.emit('aba', 'stackoverflow!'), 500);
}, 200);
<!DOCTYPE html>
<html>
<head>
<script src="https://npmcdn.com/@reactivex/rxjs@5.0.0-beta.7/dist/global/Rx.umd.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/EventEmitter/5.1.0/EventEmitter.min.js"></script>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>

</body>
</html>

这可能吗?

我希望这能解释我正在寻找的东西。

在我写这篇文章的时候,我在想一个带有Subjects 的解决方案可能就是我所需要的。我不确定,但我只需要朝着正确的方向插入或可能的话找到解决方案。

最佳答案

对于 rxjs > v7,参见 this answer


回答

果然我对使用 Subjects 的看法是正确的。关键是 Subject 的观察者列表。这是我最终所做的:

let emitting = new EventEmitter();
let sub = new Rx.Subject();

// return this to users
let myGlobalSub = sub.merge(Rx.Observable.of(1, 2, 3));

// For internal use
let myObservers = Rx.Observable.fromEvent(emitting, 'evt');

console.log(`The number of subscribers is ${sub.observers.length}`);

// Only do something if myGlobalSub has subscribers
myObservers.subscribe(l => {
if (sub.observers.length) { // here we check observers
console.log(l);
}
});

// Somewhere in the code...
emitting.emit('evt', "I don't want to see this"); // No output because no subscribers

myGlobalSub.subscribe(l => console.log(l)); // One sub

emitting.emit('evt', 'I want to see this'); // Output because of one sub

console.log(`The number of subscribers is ${sub.observers.length}`);
<!DOCTYPE html>
<html lang=en>

<head>
<script src="https://unpkg.com/rxjs@5.5.11/bundles/Rx.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/EventEmitter/5.2.5/EventEmitter.min.js"></script>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>

<body>
</body>

</html>

关于javascript - RxJS 检测 observable 何时被订阅,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44555615/

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