java - 方法——继续

Question

import java.util.Scanner;
public class InteractiveRectangle
{
public static void main(String[] args)
{
    do 
    { 
        int length = readInteger ("For Length ");
        System.out.println();
        int width = readInteger ("For Width ");
        printRectangleDetails(length,width);// existing code goes here 
    } 
    while (keepGoing()); 

    System.out.println("Goodbye, friend"); 
}


/**
 * returns the details of the rectangle
 * @param height the height of the rectangle
 * @param width the width of the rectangle
 */
public static void printRectangleDetails (int length, int width)
{
    System.out.println ("This is the length of the rectangle " + length);

    System.out.println ("This is the width of the rectangle " + width);

    System.out.println (("This is the perimeter of the rectangle " + (length + width)));

    System.out.println (("This is the area of the rectangle " + (length * width)));
}

/**
 * Read in an integer and return its value
 * @param the prompt to be shown to the user
 */
public static int readInteger(String prompt)
{
    System.out.println (prompt);
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter an integer");

    while (!scan.hasNextInt()) // while non-integers are present
    {
        scan.next();
        System.out.println ("Bad input. Enter an integer.");
    }
    int input = scan.nextInt();
    return input;
}

/**
 * Read a positive integer and return its value
 * @param the prompt to be shown to the user
 */
public static int readPositiveInteger(String prompt)
{
    System.out.println (prompt);
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter an integer");
    boolean positive = false;

    while (scan.hasNextInt() && positive == false)
    {
        int input = scan.nextInt();
        if (input > 0)
        {
            positive = true;
            {
                return input;
            }
        }
        else
        {
            System.out.println ("Bad input enter an integer.");
            positive = false;
            scan.nextLine();

        }

    }
    return 0;
}

/**
 * Ask the user whether or not to spawn another rectangle
 * and returns the result as a boolean
 */
public static boolean keepGoing()    
{
    Scanner scan = new Scanner(System.in);
    boolean inputRead = false;
    boolean result = false;
    System.out.println ("Do you want to process another rectangle?"); 
    scan.next();
    String input = scan.next();

    if (input == "y")
    {
        inputRead = true;
        result = true;

    }
    else if (input == "n")
    {
        inputRead = true;
        result = false;

    }
    else
    {
        System.out.println("Bad input please try again!");
        scan.nextLine();
    }
    return result;

}

我希望程序询问用户是否要生成另一个矩形，并继续下去，直到用户用“n”回答这个问题。 Atm 当我运行程序时，矩形只产生一次，所以我认为我的 keepGoing 方法有问题。任何帮助，将不胜感激，谢谢!

Answer 1

if (input == "y")

总是用equals()比较字符串

你需要

if ("y".equals(input))

或

if ("y".equalsIgnoreCase(input))//也将允许 Y

相应地更改其他检查。