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mysql - 模拟mysql中的排名(无排名)有两个条件

转载 作者:行者123 更新时间:2023-11-29 09:52:36 25 4
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来自这个答案:Rank based on two columns

我有以下示例:

CREATE TABLE tmpPoradi 
(`player` int, `wins` int, `diff` int)
;

INSERT INTO tmpPoradi
(`player`, `wins`, `diff`)
VALUES
(1, 10, 12),
(2, 8, 2),
(3, 10, 10),
(4, 8, 1),
(5, 8, 7),
(6, 10, 14),
(8, 10, 10),
(7, 12, 3)
;

并且期望的结果必须是:

+--------+------+------+------+
| player | wins | diff | rank |
+--------+------+------+------+
| 7 | 12 | 3 | 1 |
| 6 | 10 | 14 | 2 |
| 1 | 10 | 12 | 3 |
| 3 | 10 | 10 | 4 |
| 8 | 10 | 10 | 4 |
| 5 | 8 | 7 | 5 |
| 2 | 8 | 2 | 6 |
| 4 | 8 | 1 | 7 |
+--------+------+------+------+

问题是原始答案返回行数:

 SELECT player, wins, diff,rank from
(
SELECT player, wins, diff, @winrank := @winrank + 1 AS rank
from tmpPoradi,(SELECT @winrank := 0) r
ORDER BY wins DESC,diff DESC
) rt
ORDER BY rank

返回:

+---------+-------+-------+-------+
| player | wins | diff | rank |
+---------+-------+-------+-------+
| 7 | 12 | 3 | 1 |
| 6 | 10 | 14 | 2 |
| 1 | 10 | 12 | 3 |
| 3 | 10 | 10 | 4 |
| 8 | 10 | 10 | 5 |
| 5 | 8 | 7 | 6 |
| 2 | 8 | 2 | 7 |
| 4 | 8 | 1 | 8 |
+---------+-------+-------+-------+

我的条件尝试返回以下结果:(不知道为什么)

  SELECT player, wins, diff,rank from
(
SELECT player, wins, diff, @winrank := IF(wins = diff,@winrank,@winrank + 1) AS rank
from tmpPoradi,(SELECT @winrank := 0) r
ORDER BY wins DESC,diff DESC
) rt
ORDER BY rank


+---------+-------+-------+-------+
| player | wins | diff | rank |
+---------+-------+-------+-------+
| 7 | 12 | 3 | 1 |
| 6 | 10 | 14 | 2 |
| 3 | 10 | 10 | 3 |
| 8 | 10 | 10 | 3 |
| 1 | 10 | 12 | 3 |
| 5 | 8 | 7 | 4 |
| 2 | 8 | 2 | 5 |
| 4 | 8 | 1 | 6 |
+---------+-------+-------+-------+

所以问题是:

我做错了什么,如何通过胜利获得排名,然后如果胜利平局,则按差异进行子排名,然后如果差异平局,排名相同?

最佳答案

<强> SQL DEMO

  SELECT player, wins, diff, dense_rank, rank, dense_val, prev_wins, prev_diff
FROM
(
SELECT player,
wins,
diff,
@dense_rank := IF(wins = @prev_wins and diff = @prev_diff, @dense_rank, @dense_rank + @dense_val ) AS dense_rank,
@dense_val := IF(wins = @prev_wins and diff = @prev_diff, @dense_val + 1 , 1) as dense_val,
@rank := @rank + 1 as rank,
@prev_wins := wins as prev_wins,
@prev_diff := diff as prev_diff

FROM tmpPoradi,(SELECT @dense_rank := 0, @dense_val := 1, @rank := 0, @prev_wins := 0, @prev_diff := 0) r
ORDER BY wins DESC,diff DESC
) rt
ORDER BY rank

输出

enter image description here

关于mysql - 模拟mysql中的排名(无排名)有两个条件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54541227/

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