arrays - bash:找到文件中的所有正则表达式并放入数组

Question

我有一个包含 PlaceHolders 的模板配置文件，我想找到所有这些 PlaceHolders 并将其放入一个数组中。

当前状态:
仅当行中不超过一个 PlaceHolder时，我才能在文件中找到所有PlaceHolder。

例如，这是我的模板文件:

upstream portal {        
   server {{UNICORN_SERVICE_NAME}}:{{UNICORN_SERVICE_PORT}};  
}

server {
  listen *:80 default_server;         
  server_name {{APP_HOST}};     
  server_tokens off;     
  root /dev/null;

  # Increase this if you want to upload large attachments
  # Or if you want to accept large git objects over http
  client_max_body_size {{NGINX_MAX_UPLOAD_SIZE}};

  location {{GITLAB_RELATIVE_URL_ROOT}}/ {
    root /var/lib/nginx/portal;
    # serve static files from defined root folder;.
    # @gitlab is a named location for the upstream fallback, see below    
  }
  }

这是我用来查找占位符的代码:

matches_bloc=$(awk 'match($0, /(\{\{)([^{]*)(\}\})/) {
                    print substr($0, RSTART, RLENGTH)                    
                }' ${currFile})

            # convert 'matches_bloc' into array
            matches=()
            echo "Matches:"
            while read -r line; do
                matches+=("$line")
                echo "  - ${line}"
            done <<< "$matches_bloc"

在此示例中，匹配结果将是:

Matches:
- {{UNICORN_SERVICE_NAME}}
- {{APP_HOST}}
- {{NGINX_MAX_UPLOAD_SIZE}}
- {{GITLAB_RELATIVE_URL_ROOT}}

您可以注意到文件中有 5 个 PlaceHolder，但只有 4 个匹配项。
缺少的匹配项是:{{UNICORN_SERVICE_PORT}}，因为同一行中已经有另一个匹配项。

我的问题是:
我怎样才能找到文件中的所有匹配项而不考虑行？

Answer 1

找到模板文件中的所有变量并将它们放入一个数组中。

与 GNU grep :

array=( $(grep -Po '{{.*?}}' file) )
declare -p array

输出:

declare -a array='([0]="{{UNICORN_SERVICE_NAME}}" [1]="{{UNICORN_SERVICE_PORT}}" [2]="{{APP_HOST}}" [3]="{{NGINX_MAX_UPLOAD_SIZE}}" [4]="{{GITLAB_RELATIVE_URL_ROOT}}")'

-P: Interpret {{.*?}} as a Perl regular expression.

-o: Print only the matched (non-empty) parts of a matching line, with each such part on a separate output line.

* The preceding expression can match zero or more times. With ? the * tries to match as few as possible (non-greedy).

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参见:The Stack Overflow Regular Expressions FAQ