java - Java中的开关正在循环

Question

我的 switch 语句一直在循环。它应该打印您选择的选项，然后重新打印菜单。请帮忙!这是我的代码:

menu ="\n\t1  Create Account" + 
            "\n\t2  Check balance" +
            "\n\t3  Withdraw" +
            "\n\t1  Deposit" + 
            "\n\t2  Get account ID" +
            "\n\t3  Set ID" +
            "\n\t1  Display Account Info" +

            "\n\t0  Quit\n\n\n";

    System.out.println(menu);
    System.out.println("\tEnter your selection:  ");
    option = scan.nextInt();

while (option != 0) {

            switch (option) {

            case 1: //  Enter and Validate SSN
                        System.out.print("option 1");
                        break;

            case 2:     //Enter and Validate Passwords
                        System.out.print("option 2");
                        break;

            case 3:     //Enter,Verify, and Translate a Phone keypad Number
                        System.out.print("option 3");
                        break;

            case 4: //  Enter and Validate SSN
                        System.out.print("option 4");
                        break;

            case 5:     //Enter and Validate Passwords
                        System.out.print("option 5");
                        break;

            case 6:     //Enter,Verify, and Translate a Phone keypad Number
                        System.out.print("option 6");
                        break;

            case 7:     //Enter,Verify, and Translate a Phone keypad Number
                        System.out.print("option 7");
                        break;

            default: outputString = "\nInvalid Selection\n";
                        System.out.println(outputString);
                        break;

        }
    }

Answer 1

我很确定是您的 while 循环在执行循环。而且您永远不会在循环体内更改 option 的值，因此它当然会连续运行。

大概，你想移动这条线:

option = scan.nextInt();

到循环的第一行:

while (option != 0) {
    option = scan.nextInt();
    ... 
}