string - grep 两个文件 (a.txt, b.txt) - b.txt 中有多少行以 a.txt 中的单词开始(或结束) - 输出 : 2 files with the results

Question

我知道我要求太多，但也许你也可以帮助解决这个问题。

a.txt 包含单词，b.txt 包含字符串。

我想知道 b.txt 中有多少个字符串以 a.txt 中的单词结尾

例子:一个.txt

apple
peach
potato

b.txt

greenapple
bigapple
rottenapple
pinkpeach
xxlpotatoxxx

输出

3 apple greenapple bigapple rottenapple
1 peach pinkpeach

我想用 grep 来解决，因为它比 awk 快得多。

你们能帮帮我吗？

Answer 1

这是一个awk的解决方案

awk 'FNR==NR{a[$1]++;next} {for (i in a) {if ($0~i"$") {b[i]++;w[i]=w[i]?w[i] FS $0:$0}}} END {for (j in b) print b[j],j,w[j]}' a.txt b.txt
3 apple greenapple bigapple rottenapple
1 peach pinkpeach

用 grep

做到这一点并不简单或根本不可能

它是如何工作的(没那么复杂)？

awk '
FNR==NR{                        # Run this part for first file (a.txt) only
  a[$1]++                       # Store it in an array a
  next}                         # Skip to next record
  {                             # Run this part for file b.txt
  for (i in a) {                # Loop trough all data in array a
    if ($0~i"$") {              # Does b.txt have some from array a at the end of it?
      b[i]++                    # Yes , count it
      w[i]=w[i]?w[i] FS $0:$0   # and store the record it found it in in array w
      }
    }
  } 
END {                           # When both file has been read do the END part
  for (j in b)                  # Loop trough all element in array b and
    print b[j],j,w[j]}          # Print array b, index and array w
  ' a.txt b.txt                 # Read the two files